Question

For many purposes we can treat nitrogen as an ideal gas at temperatures above its boiling point of - 196.°C.

Answer 1

Answer:

Explanation:

P1V1=n1RT1

P2V2=n2RT2

n1=n2  R=R

Divide equals and get

P1V1T2=P2V2T1

V2 =V1 (P1/P2)(T2/T1)

V2 will reduce by 10% due to pressure

V2 will increase by 184K/175K or 5%

therefor overall V will decrease

about 5%

Answer 2

Answer: the volume of the sample decreased

Explanation:

T1 = -98°C = - 98 + 273 = 175K

T2 = -89°C = -89 +273 = 184K

P1 = P

P2 = 110%P = 1.1P

V1 = V

V2 =?

P1V1/T1 = P2V2/T2

PxV/175 = 1.1PxV2/184

175x1.1PxV2 = PVx 184

V2 = (PVx 184) /(175x1.1P)

V2 = 0.96V = 96%V

Therefore, the final volume is 96% of the initial volume. This means that the final volume decreased by 96%