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DENIUS [597]
3 years ago
12

For many purposes we can treat nitrogen as an ideal gas at temperatures above its boiling point of - 196.°C.

Chemistry
2 answers:
Slav-nsk [51]3 years ago
4 0

Answer:

Explanation:

P1V1=n1RT1

P2V2=n2RT2

n1=n2  R=R

Divide equals and get

P1V1T2=P2V2T1

V2 =V1 (P1/P2)(T2/T1)

V2 will reduce by 10% due to pressure

V2 will increase by 184K/175K or 5%

therefor overall V will decrease

about 5%

Pavel [41]3 years ago
3 0

Answer: the volume of the sample decreased

Explanation:

T1 = -98°C = - 98 + 273 = 175K

T2 = -89°C = -89 +273 = 184K

P1 = P

P2 = 110%P = 1.1P

V1 = V

V2 =?

P1V1/T1 = P2V2/T2

PxV/175 = 1.1PxV2/184

175x1.1PxV2 = PVx 184

V2 = (PVx 184) /(175x1.1P)

V2 = 0.96V = 96%V

Therefore, the final volume is 96% of the initial volume. This means that the final volume decreased by 96%

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List the subshells that hold the 25 electrons in a<br> manganese atom in order of increasing energy
jonny [76]

Answer:

1s2 2s2 2p6 3s2 3p6 4s2 3d5

Explanation:

According to the Aufbau principle, electrons are filled in orbitals in order of increasing energy. The energy of orbitals in the electronic configuration of manganese increases from left to right, hence 3d orbital is much greater in energy than a 3p orbital.

The arrangement of orbitals in order of increasing energy is shown in the answer above.

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3 years ago
The speed of sound through air at 20°C is 343 meters per second. The speed of sound through fresh water at 20°C is 1,482 meters
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Answer:

C. 5960 meters per second

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2 years ago
How many pili are in a bacterial cell
Snowcat [4.5K]

Answer: Bacterial species where observed Typical number on cell Distribution on cell surface

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Pseudomonas aeruginosa 10-20 polar

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Pili are structures that extend from the surface of some bacterial cells.

These are hollow, non-helical, filamentous appendages.

Hope it helps you

7 0
2 years ago
Paleontologists have discovered several ancestors of the modern horse.
ExtremeBDS [4]

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8 0
3 years ago
Read 2 more answers
Pls helpits rlly hard
victus00 [196]

Answer:

5: 0.16

6: 50

Explanation:

Question 5:

We can use the equation density = mass/ volume.

We already have the mass (12g), but now we need to find the volume of the cylinder.

The equation for this is πr²h

So we know the radius is 2 and the height is 6.

π x (2)² x 6 = 24π = 75.398cm³

Now we can use the density equation above:

12/75.398 = 0.1592g/cm³ = 0.16g/cm³.

Question 6:

This time, we have to rearrange the equation density = mass/ volume to find the mass.

We know mass = density x volume.

From the question, the density is 2.5g/mL and the volume is 20mL.

Following the equation above, we do 2.5 x 20 to get 50g.

5 0
2 years ago
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