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dimaraw [331]
3 years ago
11

5. Before vehicle emissions were well-regulated CO emissions were 66 g/mile. Assume this emission rate applies for an airshed. T

he airshed has dimensions of 9 km by 18 km with wind speeds of 1.5 m/s parallel to the longer dimension. There is a temperature inversion at 100 m. The average vehicle miles traveled is 800,000 miles each hour between 5 AM and 8 PM, and the concentration of CO before the morning rush hour and the incoming wind concentration are both 200 ppb. Temperature is 0 °C and pressure is 0.9 atmospheres. a. Find C0 and Cin in mg/m3 . b. What is the pollutant residence time in the box? c. If morning rush hour starts at 5 AM. What is the CO concentration seven hours later?
Chemistry
1 answer:
Aleks [24]3 years ago
4 0

Answer:CALINE4 Model and Geographical Information System were used for

the present study to predict the CO concentrations and prepare thematic

maps for the study area.

CALINE4 is a latest model that predicts the concentration of carbon

monoxide impacts near the roadways. The California Department of

Transformation (CALTRANS) developed the model and its purpose is to help

planners protect public health from the adverse effects of carbon monoxide.

The model predictions along with the aid of GIS based model help to arrive at

air shed levels of carbon monoxide. CALINE4 is a simple line source

Gaussian plume dispersion model. The user defines the proposed roadway

geometry, worst-case meteorological parameters, anticipated traffic volumes

and receptor positions to predict the concentrations of pollutant.

CALINE4 is graphical with windows based user interface, designed to

ease data entry and increase the online help capabilities. The model was

developed for predicting the concentrations of relatively inert pollutants such

as carbon monoxide and it is now used for several other pollutants like NO2

and SPM. The model is based on fine tuned Gaussian diffusion equation and

it employs mixing zone concept to characterize the pollutant dispersion over

the roadways. Given the exhaust emission concentrations, meteorology and

site geometry, the model can predict the concentration of pollutants for any experimentation

Explanation:

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What is the correct formula of a compound that has ten oxygen atoms and four phosporus atoms?
Arte-miy333 [17]

The correct formula of a compound that has ten oxygen atoms and four phosphorus atoms will be P_{4} O_{10}<u>(tetra phosphorus decoxide)</u>

<u />

Chemical element symbols, numbers, and other symbols, such as parentheses, dashes, brackets, commas, plus as well as minus signs, are used to represent the chemical quantities of the atoms that make up a certain chemical compound and molecule.

It is given that the number of P atom is 4 and 10 oxygen . Decoxide mean

any oxide with ten oxygen molecules per molecule.

Typically, a molecular molecule consists of two or even more nonmetal components. Molecular compounds are characterized by employing the stem of the primary element's term plus the suffix -ide, followed by the second element. The count of atoms in a molecule is specified using numerical prefixes.

Therefore, The correct formula of a compound that has ten oxygen atoms and four phosphorus atoms will be P_{4} O_{10}<u>(</u><u>tetra phosphorus decoxide)</u>

<u />

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7 0
2 years ago
Which is a characteristic of nuclear fission?
FinnZ [79.3K]
A nucleus spontaneously splits and absorbs energy.
4 0
2 years ago
What is the volume of liquid in this graduated cylinder? Be sure your answer has a reasonable number of decimal places.
Amiraneli [1.4K]

Answer:

76 ml

Explanation:

The complete question is attached in the image.

The volume of a liquid is the amount of space that the liquid occupies or contains. Since for a liquid, it takes the shape of the container, when measuring the volume, we just measure the space occupied by the liquid in the container.

From the image, when determining the volume, we are to use the value of the lower meniscus. Hence the volume of the liquid is gotten to be 76 ml

8 0
3 years ago
The fermentation of glucose (C6H12O6) produces ethyl alcohol (C2H5OH) and CO2:
Jlenok [28]
To answer your question I will use dimensional analysis, which is used by cancelling out the units. I will also use the balanced equation provided as a conversion factor.

A) First start out with the 0.300 mol of C6H12O6...
0.300 mol C6H12O6 * (2 mol CO2 / 1 mol C6H12O6) = 0.600 mol CO2

*The significant figures (sig figs) at still three, the 2 is a conversion counting number and does not count*

B) First change 2.00 g of C2H5OH to moles of C2H5OH...
The molecular mass of C2H5OH is...
2(12.01 g/mol) + 5(1.008 g/mol) + 16.00 g/mol + 1.008 g/mol = 46.07 g/mol
This can be used as a conversion factor to change grams to moles. 
2.00 g C2H5OH * (1 mol C2H5OH / 46.07 g C2H5OH) = 0.0434 mol C2H5OH

Second, you can change the moles of C2H5OH to moles of C6H12O6..
0.0434 mol C2H5OH * (1 mol C6H12O6 / 2 mol C6H12O6) = 0.0217 mol C6H12O6

Third, change moles of C6H12O6 to grams...
MM = 6(12.01 g/mol) + 12(1.008 g/mol) + 6(16.00 g/mol) = 180.16 g/mol
0.0217 mol C6H12O6 * (180.16 g C6H12O6 / 1 mol C6H12O6) = 3.91 g C6H12O6

C) Now I am going to put it all into one long dimensional analysis problem.
MM of CO2 = 44.01 g/mol
MM of C2H5OH = 46.07 g/mol

2.00 g C2H5OH * (1 mol C2H5OH / 46.07 g C2H5OH) * (2 mol CO2 / 2 mol C2H5OH) * (44.01 g CO2 / 1 mol CO2) = 1.91 g CO2

I hope this helped and I am sorry that I talked to much, I just didn't want to miss anything!
3 0
3 years ago
the atomic number of four elements p,q,r,s are 6,8,10 and 12 respectively. the two elements which can bond ionically are:
denis-greek [22]

Answer:

The atomic numbers of four elements A, B, C, and D are 6,8,10, and 12 respectively. The two elements which can react to form ionic bonds (or ionic compounds) are B (8= 2,6) and D (12 =2,8,2). So D donates its two electrons to B to fulfill their octet.

Explanation:

6 0
2 years ago
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