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dimaraw [331]
3 years ago
11

5. Before vehicle emissions were well-regulated CO emissions were 66 g/mile. Assume this emission rate applies for an airshed. T

he airshed has dimensions of 9 km by 18 km with wind speeds of 1.5 m/s parallel to the longer dimension. There is a temperature inversion at 100 m. The average vehicle miles traveled is 800,000 miles each hour between 5 AM and 8 PM, and the concentration of CO before the morning rush hour and the incoming wind concentration are both 200 ppb. Temperature is 0 °C and pressure is 0.9 atmospheres. a. Find C0 and Cin in mg/m3 . b. What is the pollutant residence time in the box? c. If morning rush hour starts at 5 AM. What is the CO concentration seven hours later?
Chemistry
1 answer:
Aleks [24]3 years ago
4 0

Answer:CALINE4 Model and Geographical Information System were used for

the present study to predict the CO concentrations and prepare thematic

maps for the study area.

CALINE4 is a latest model that predicts the concentration of carbon

monoxide impacts near the roadways. The California Department of

Transformation (CALTRANS) developed the model and its purpose is to help

planners protect public health from the adverse effects of carbon monoxide.

The model predictions along with the aid of GIS based model help to arrive at

air shed levels of carbon monoxide. CALINE4 is a simple line source

Gaussian plume dispersion model. The user defines the proposed roadway

geometry, worst-case meteorological parameters, anticipated traffic volumes

and receptor positions to predict the concentrations of pollutant.

CALINE4 is graphical with windows based user interface, designed to

ease data entry and increase the online help capabilities. The model was

developed for predicting the concentrations of relatively inert pollutants such

as carbon monoxide and it is now used for several other pollutants like NO2

and SPM. The model is based on fine tuned Gaussian diffusion equation and

it employs mixing zone concept to characterize the pollutant dispersion over

the roadways. Given the exhaust emission concentrations, meteorology and

site geometry, the model can predict the concentration of pollutants for any experimentation

Explanation:

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5. Inside the mouth, these cells are joined together in a sheet. Why are they scattered here?
anyanavicka [17]

Answer:

Inside the mouth, these cells are joined together in a sheet. Why are they scattered here? They are scattered here because we disrupted there original form by scrapping them off our mouths and smearing them on the slide.

Explanation:

5 0
3 years ago
Determine the number of molecules in a 100. gram sample of CCl4
enyata [817]
100. g CCl4* (1 mol CCl4/ 153.8 g CCl4)* (6.02*10^23 CCl4 molecules/ 1 mol CCl4)= 3.91*10^23 CCl4 molecules.
(Note that the units cancel out so you get the answer)

Hope this helps~
8 0
3 years ago
1. How much energy (in KJ) is required to convert 50.0g of ice at – 30 ˚C to<br> steam at130˚C.
Vitek1552 [10]

Answer:

How much heat energy required to convert following?

How much heat energy, in kilojoules, is required to convert 47.0 g of ice at -18.0 C to water at 25.0 C ?

Specific Heat of Ice - 2.09 j/g * c

This is how I did it and the answer is wrong...Please check and correct me

Q = m * Cice * Change in Temp

Q = (47.0 g)(2.09 J/g*c)(43) = 4222.6 J * 0.001 kj / j = 4.22 kj

4 0
2 years ago
At what Celsius temperature does 0.750 mol of an ideal gas occupy a volume of 35.9 L at 114 kPa?
shepuryov [24]

382.85  Celsius is the temperature does 0.750 moles of an ideal gas occupy a volume of 35.9 L at 114 kPa.

Explanation:

Given data:

number of moles of the gas  = 0.75 moles

volume of the gas = 35.9 liters

pressure of the gas = 114 KPa or 1.125 atm

R = 0.0821 latm/moleK

temperature of the gas T = ?

The equation used to calculate temperature from above data is ideal gas law equation.

the equation is :

PV = nRT

T = \frac{PV}{nR}

Putting the values in the above rewritten equation:

T = \frac{1.125 X 35.9}{0.75 X 0.0821}

T = 655.9 K

To convert kelvin into celsius, formula used is

K = 273.15+ C

putting the values in the equation

C = 656 - 273.15

   = 382.85  Celsius

8 0
3 years ago
chlorine has 7 outer energy level electrons and argon has 8. what is the difference in the reactivity of these two elements?
Lunna [17]
Chlorine is more reactive than argon, because argon is not reactive at all. Chlorine only has to gain 1 valence electron
6 0
3 years ago
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