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dimaraw [331]
3 years ago
11

5. Before vehicle emissions were well-regulated CO emissions were 66 g/mile. Assume this emission rate applies for an airshed. T

he airshed has dimensions of 9 km by 18 km with wind speeds of 1.5 m/s parallel to the longer dimension. There is a temperature inversion at 100 m. The average vehicle miles traveled is 800,000 miles each hour between 5 AM and 8 PM, and the concentration of CO before the morning rush hour and the incoming wind concentration are both 200 ppb. Temperature is 0 °C and pressure is 0.9 atmospheres. a. Find C0 and Cin in mg/m3 . b. What is the pollutant residence time in the box? c. If morning rush hour starts at 5 AM. What is the CO concentration seven hours later?
Chemistry
1 answer:
Aleks [24]3 years ago
4 0

Answer:CALINE4 Model and Geographical Information System were used for

the present study to predict the CO concentrations and prepare thematic

maps for the study area.

CALINE4 is a latest model that predicts the concentration of carbon

monoxide impacts near the roadways. The California Department of

Transformation (CALTRANS) developed the model and its purpose is to help

planners protect public health from the adverse effects of carbon monoxide.

The model predictions along with the aid of GIS based model help to arrive at

air shed levels of carbon monoxide. CALINE4 is a simple line source

Gaussian plume dispersion model. The user defines the proposed roadway

geometry, worst-case meteorological parameters, anticipated traffic volumes

and receptor positions to predict the concentrations of pollutant.

CALINE4 is graphical with windows based user interface, designed to

ease data entry and increase the online help capabilities. The model was

developed for predicting the concentrations of relatively inert pollutants such

as carbon monoxide and it is now used for several other pollutants like NO2

and SPM. The model is based on fine tuned Gaussian diffusion equation and

it employs mixing zone concept to characterize the pollutant dispersion over

the roadways. Given the exhaust emission concentrations, meteorology and

site geometry, the model can predict the concentration of pollutants for any experimentation

Explanation:

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Which property can be used to tell gold and pyrite apart?
zubka84 [21]

Answer:

D. Malleability

Explanation:

Gold is made up of the element Au and it is a metal.

Pyrite is iron sulfide and it is a non-metal.

  • They have very similar appearance to such an extent that pyrite is widely called the fool's gold.
  • To distinguish between the two, we simply explore their metallic properties.
  • Gold is malleable. Pyrite is not. It will crumble under pressure.
6 0
3 years ago
Pls help ASAP........ A student was roasting marshmallows over a fire. The student
Phantasy [73]

Answer:

A chemical change

Explanation:

The marshmallow turning brown and bubbling implies that a chemical change has taken place.

For chemical changes to occur, we observe any of the following:

  • a new kind of matter is formed.
  • it is always accompanied by energy changes
  • the process is not easily reversible
  • it involves a change in mass
  • requires considerable amount of energy.

ii. Two signs that shows a chemical change has taken place is that:

  • bubbles are being formed as it is roasted and it implies that new substances have been formed.
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5 0
2 years ago
Which of the following represents a chemical change?
Nikitich [7]

Answer:

Option B : burning of wood

Explanation:

Chemical change is a change where a new substance is created like when you will bur wood you get ash this is a new substance, so burning of wood is a chemical change.

 

7 0
3 years ago
Please answer this questions soon<br><br>i will mark him or her brillient<br>​
Misha Larkins [42]

Answer:

1)Or

d.Sublimation

2)

b.iodine is the solute and alcohol is solvent

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a.compostion of solute

4 0
2 years ago
Read 2 more answers
A compound with a molar mass of 100.0 g/lol has an elemental composition of 24.0% C, 3.0% H, 16.0% O and 57.0%F. What is the mol
ch4aika [34]

If I made no mistake in calculation, the given answer must be correct...(tried my best)



elements   :                        carbon     hydrogen    oxygen       Fluorine

 composition [C]                     24             3                16                57

M r                                          12             1                16                19

(divide C by Mr)                       2               3                 1                  3


(Divide by smallest value)       2                3                  1                  3

(smallest value = 1...so all value remained constant)

Empirical formula : C2H3OF3


if molar mas = 100 g per mole, then

first step calculate Mr. of empirical formula:  [= 100]


Them molecular formula = empirical formula

    
7 0
3 years ago
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