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erma4kov [3.2K]
3 years ago
12

The potential energy diagram shows the gain and loss of potential energy as water molecules decompose into hydrogen and oxygen.

Label the parts of the diagram

Chemistry
1 answer:
Dovator [93]3 years ago
4 0

Answer:

  • The<em> diagram</em> with the five<em> labels</em> of the parts is in the image attached. Please, see the image.

Explanation:

<u>1) General explanation:</u> a <em>potential chemical energy diagram</em> is used to show how the <em>reactants</em> gain energy until they reach the <em>activation energy</em>, form the <em>activated complex</em>, and release part of the energy to form the <em>products</em>.

The difference between the chemical potential energy of the products and the reactants is the <em>enthalpy of the reaction</em>:

  • ΔH rxn = ΔH products - ΔH reactants.

The labels that correspond to each part of the diagram are explained next.

<em><u>2) Reactants:</u></em>

This is the substances at the start, so they appear on the left bottom side of the diagram.

<em><u>3) Activation energy:</u></em>

It is the energy that the reactants must reach (the highest point) in order to the reaction occurs.

<u><em>4) Activated complex:</em></u>

This is the intermediate state and of highest energy. The reactants have formed a complex at mid way between the reactants and the products.

<u><em>5) Products:</em></u>

These are the substances formed when the reaction is completed. They are lower in energy than the activated complex. They can be either higher or lower in energy than the reactants. The products are shown to the right of the diagram.

<em><u>6) Enthalpy of the reaction:</u></em>

The enthalpy of the reaction is the difference in energy of the products and the reactants. In this case, since, the products are higher in energy, it means that the reaction absorbed energy and it is an endothermic reaction.

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Halogens such as chlorine, bromine and iodine have properties that enable them to react with other elements to form important salts such as sodium chloride, also known as table salt.

Explanation:

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True or false The density of a subsidence is always the same
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The answer is true that it right and that’s what I said
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Compare the solubility of a fatty acid and a fatty acid salt in water. Compare the solubility of a fatty acid and a fatty acid s
anyanavicka [17]

Answer:

The correct option is A. The salt is more soluble in water since it can form stronger ion-dipole interactions not available to the fatty acid.

Explanation:

An ion-dipole interaction occurs when an ionic compound is placed in a polar solvent. As salts are ionic compounds and water is a polar solvent, so the fatty acid salts will be able to form electrostatic ion-dipole interactions with the polar water molecules. These interactions will cause fatty acid salts to dissolve in water.

The fatty acid is not an ionic compound and will not form the ion-dipole interactions with the water molecules. Hence, fatty acids will be less soluble in water.

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Calcium dihydrogen phosphate, Ca(H₂PO₄)₂, and sodium hydrogen carbonate, NaHCO₃, are ingredients of baking powder that react to
Gre4nikov [31]

0.012 mol of CO₂ is the volume of CO₂ is produced from 1.00 g of baking powder.

Balanced Equation:

Ca(H₂PO₄)₂(s) + 2NaHCO₃(s) → 2CO₂(g) + 2H₂O(g) + CaHPO₄(s) + Na₂HPO₄(s)

On 3.50 g of baking powerd:

mCa(H₂PO₄)₂ = 0.35*3.50 = 1.225 g

mNaHCO₃ = 0.31*3.50 = 1.085 g

The molar masses are: Ca = 40 g/mol; H = 1 g/mol; P = 31 g/mol; O = 16 g/mol; Na = 23 g/mol; C = 12 g/mol. So:

Ca(H₂PO₄)₂: 40 + 4x1 + 31 + 8x16 = 203 g/mol

NaHCO₃: 23 + 1 + 12 + 3x16 = 84 g/mol

The mass divided by the molar mass yields the number of moles, as in:

nCa(H₂PO₄)₂ = 1.225/203 = 0.006 mol

nNaHCO₃ = 1.085/84 = 0.0129 mol

Find the reactant that is limiting first. The stoichiometry for the Ca(H₂PO₄)₂ test is:

1 mol of Ca(H₂PO₄)₂ ---------- 2 mol of NaHCO₃

0.006 of Ca(H₂PO₄)₂ -------- x

By a simple direct three rule:

x = 0.012 mol

NaHCO₃ is therefore too much. After performing the stoichiometry calculus with the limiting reactant:

1 mol of Ca(H₂PO₄)₂ ------------- 2 mol of CO₂

0.006 of Ca(H₂PO₄)₂ -------- x

By a simple direct three rule:

x = 0.012 mol of CO₂

What is molar mass and how is it calculated?

The mass of every atom in a molecule, expressed in grams per mole, is known as the molar mass. We first obtain the atomic weights of the different elements in a periodic table in order to compute the molar mass of a molecule. Then, we multiply the total number of atoms by each one's atomic mass.

How is molar mass calculated and why is it important?

When converting a mass measurement to a substance amount, the molar mass ratio is utilized. The number of atoms, molecules, or ions that make up this quantity is used to express it. It is the proportion of an object's mass to the quantity of its constituent particles.

Learn more about molar mass: brainly.com/question/13152455

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5 0
1 year ago
The freezing point of camphor is 178.4�c and its molal freezing point depression constant (kf) is 37.7�c�kg/mol. how many grams
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Answer :

The correct answer is : 0.34 g of naphthalene .

Step 1 : To find molaity of solution using freezing point depression formula .

The formula for Freezing point depression is :ΔTf = kf * m

where , ΔTf = Freezing point of solvent - freezing point of solution

kf = freezing point depression constant and m = molality .

Given : Freezing point of solvent (camphor ) = 178.4 °C

Freezing point of solution ( naphthalene in camphor) = 170.0°C

kf for camphor = 37.7 °C Kg /mol

Plugging values in ΔTf - kf *m

178.4 °C - 170.0°C = 37.7 °C Kg/mol * m

8.4 °C = 37.7 °C Kg/mol * m

Dividing both side by 37.7 °C Kg/mol to isolate m

8.4 °C /37.7°C Kg/mol = 37.7 °C Kg/mol / 37.7 °C Kg/mol * m

m (molality ) = 0.22 mol/Kg

Step 2 : To find moles from molality .

Molality is moles of naphthalene ( solute ) present in kilograms of camphor (solvent ) . Formula of molality is : moles of solute / kilograms of solvent

Given mass of camphor = 12 g or 0.012 Kg ( 1 g = 0.001 Kg )

Plugging value in formula => 0.22 mol /Kg = mole of solute / 0.012Kg

mole of solute = 0.22 mol/Kg x 0.012 Kg = 0.00264 mol

Step 3 : To convert mole of naphthalene to its mass :

mass = mole x molar mass

Mass = 0.00264 mol x 128.17 g/mol

Mass of naphthalene to be added = 0.34 g

8 0
3 years ago
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