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3 years ago

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If 2.40 moles of gas are held at a temperature of 97.0 °C in a container with a volume of 45.0 L, what is the pressure of the ga

s?

1 answer:

Rainbow [258]3 years ago

7 0

PV=nRT<=> P=nRT/V=2,40*R*(273+97)/45 atm.
Calculate it. R is a number that is given, find it and use your math to solve.

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which one of the following is an endothermic process?1.ice melting 2.water freezing 3.a boiling soup 4.the reaction of HCl and N

Llana [10]

<span>From the above given choices :
melting is an endothermic process</span>

8 0

3 years ago

A solution of ammonia has a pH of 11.8. What is the concentration of OH– ions in the solution?

Basile [38]

Answer:

The answer is 2.20 M

Explanation:

This is because ammonia has a pH of 11.8 and if you take 14-11.8 it equals 2.2 so the answer is 2.20 M

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3 years ago

Read 2 more answers

Fill in the blanks with the correct term.

zzz [600]

Answer:

Fill in the blanks with the correct term.

a. a liquid that dissolves another substance.

b. a chemical that is dissolved.

c. a value used to describe the amount of one substance dissolved in another.

d. a liquid consisting of one substance dissolved in another.

Explanation:

a. A liquid that dissolves another substance is called the solvent.

b. A chemical that is dissolved solute.

c. A value used to describe the amount of one substance dissolved in another is called concentration.

d. A liquid consisting of one substance dissolved in another is called a solution.

4 0

3 years ago

How many hydrogen atoms are in a cycloalkane with 8 carbon atoms?

frosja888 [35]

Cycloalkanes are those saturated organic compounds which exist in the form of Rings. Their Hydrogen Deficiency Index in one. The General formula for cycloalkanes is,
CnH2n
When number of Carbons = 8
Then
C₈H₂₍₈₎

C₈H₁₆

Result:
Cycloalkane containing 8 carbon atoms has 16 hydrogen atoms.

8 0

3 years ago

Part A of the lab involved adding 4 mL increments of distilled water to 5.00 mL of antimony trichloride solution. The antimony t

Mrrafil [7]

Answer:

0.0238M SbCl3, 1.07M H+, 1.14M Cl-

Explanation:

The total volume of the solution is:

4mL + 5.00mL + 12.0mL = 21mL

As the volume of the SbCl3 is 5.00mL, the dilution factor is:

21mL / 5.00mL = 4.2 times

The concentration of SbCl3 is:

0.10M SbCl3 / 4.2 times = 0.0238M SbCl3

The concentration of H+ = [HCl]:

4.5M / 4.2 times = 1.07M H+

The initial concentration of Cl- is:

3 times SbCl3 + HCl = 0.10M*3 + 4.5M =

<em>3 times SbCl3 because 1 mole of SbCl3 contains 3 moles of Cl-</em>

4.8M Cl- / 4.2 times = 1.14M Cl-

3 0

2 years ago