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alexgriva [62]
3 years ago
14

If 2.40 moles of gas are held at a temperature of 97.0 °C in a container with a volume of 45.0 L, what is the pressure of the ga

s?
Chemistry
1 answer:
Rainbow [258]3 years ago
7 0
PV=nRT<=> P=nRT/V=2,40*R*(273+97)/45 atm.
Calculate it. R is a number that is given, find it and use your math to solve.
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What does a fluorine ion have in common with a neon and a sodium ion
DanielleElmas [232]
The atomic number (Z) of the 3 elements F, Ne, and Na, are 9, 10, and 11.

Explanation:

Now Z refers to the number of protons in the element's nucleus, and protons are POSITIVELY charged particles. So a fluoride ion, F−, has 10 electrons rather than 9 (why?), a neutral neon atom has 10 electrons, and a sodium ion, Na+, also has 10 electrons (why?).

So the 3 species are ISOELECTRONIC; they possess the same number of electrons. 

You should look at the Periodic Table to confirm the electron number. Elements are (usually) electrically neutral (sometimes they can be ionic if they have lost or gained electrons). If there are 10 positively charged protons in the nucleus, there are NECESSARILY 10 electrons associated with the NEUTRAL atom. I don't know WHY I am capitalizing certain WORDS.

You might ask why sodium will form a positive ion, Na+, whereas F forms a negative ion, F−. This again is a Periodic phenomenon, and explicable on the basis of the electronic structure that the Table formalizes.

Neutral metals tend to be electron-rich species, which have 1 or more electrons in a valence shell remote from the nuclear charge. On the other hand, neutral non-metals have valence electrons in incomplete shells, that do not effectively shield the nuclear charge. The demonstrable consequence is that metals lose electrons to form positive ions, whereas non-metals gain electrons to form negative ions.

6 0
3 years ago
PLEASE HELP WITH ALL
Gala2k [10]

Answer:

Question 1: D

Question 2: B C E F

Question 3: A

Question 4: A

Question 5: A

5 0
4 years ago
Read 2 more answers
Iodine-131 is administered orally in the form of NaI(aq) as a treatment for thyroid cancer. The half-life of iodine-131 is 8.04
evablogger [386]

Answer:

16.6 mg

Explanation:

Step 1: Calculate the rate constant (k) for Iodine-131 decay

We know the half-life is t1/2 = 8.04 day. We can calculate the rate constant using the following expression.

k = ln2 / t1/2 = ln2 / 8.04 day = 0.0862 day⁻¹

Step 2: Calculate the mass of iodine after 8.52 days

Iodine-131 decays following first-order kinetics. Given the initial mass (I₀ = 34.7 mg) and the time elapsed (t = 8.52 day), we can calculate the mass of iodine-131 using the following expression.

ln I = ln I₀ - k × t

ln I = ln 34.7 - 0.0862 day⁻¹ × 8.52 day

I = 16.6 mg

8 0
3 years ago
What types of evidence do scientists use to determine evolutionary relationships among groups
lions [1.4K]
There are several things that can help scientists evaluate which category something belongs to. The similarity in features is one of them. If two skulls looked alike, they were probably species of the same evolutionary category. For example say humans and monkeys rather than humans and dogs.
Similarly fossils have helped scientists categorise species. Study of the chromosomes (in cases with available chromosomes) can help scientists figure out a lot about the subjects and categorise them. 
5 0
3 years ago
Identify the atomic orbitals in the C-C sigma bond in ethyne (acetylene HC-triplebond-CH)
aleksley [76]

Answer:

Explanation:

A sigma bond is formed  when a hybrid orbital sp overlaps with another hybrid orbital or with s- or  p- orbital

Ethylene has a structural formula of  H - C≡ C- H

At the ground state; we have :

C    | ⇅ |     |↑ | ↑

        2s       2p

At the excited state, we have:

C    | ↑ |     |↑ | ↑ | ↑

the hybrid orbital

C = | ↑ | ↑ |

      2sp

8 0
4 years ago
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