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Tomtit [17]
3 years ago
5

Which of the following atoms has a full outer shell?

Chemistry
1 answer:
Liula [17]3 years ago
3 0

Magnesium has a full outer shell because it says +2 for Mg, which means it loses 2 electrons. It leaves Mg with an outer shell of 8 electrons, which is a full valence shell.

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A loss of electrons by an atom creates an anion? <br> true or false
Nostrana [21]
That is false.

An ion is "<span>an electrically charged atom or group of atoms formed by the loss or gain of one or more electrons."

But in detail anion means gaining of electrons.

So, a gain of electrons by an atom creates an anion.</span>
4 0
2 years ago
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Calculate the energy required to produce 6.0 moles of Cl2O7 using the following reaction 2 Cl2 + 7 O2 + 130kcal -&gt; 2 Cl207
PilotLPTM [1.2K]

Answer:

455 Kcal

Explanation:

2Cl2(g) + 7O2(g) + 130kcal → 2Cl2O7(g)

Rearranging we get,

2Cl2(g) + 7O2(g)  → 2Cl2O7(g) Δ H = 130 kcal . mol⁻¹

So for per mol reaction will be as above.

In case of 7 mols of product, we need 7/2 mole ratio x 130 = 455 Kcal

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What is the purpose of the dts other auths and pre audits screen?
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6 0
2 years ago
what is the limiting reactant in the reaction of 12.0 g of SO2 with 8.0 g of H2S and their reaction? what mass of sulfur will be
larisa86 [58]
The balanced equation for the reaction is as follows;
2H₂S + SO₂ —> 2H₂O + 3S
Stoichiometry of H₂S to SO₂ is 2:1
Limiting reactant is fully used up in the reaction and amount of product formed depends on amount of limiting reactant present.
Number of H₂S moles - 8.0 g / 34 g/mol = 0.24 mol of H₂S
Number of SO₂ moles = 12.0 g / 64 g/mol = 0.188 mol of SO₂
According to molar ratio of 2:1
If we assume H₂S to be the limiting reactant
2 mol of H₂S reacts with 1 mol of SO₂ 
Therefore 0.24 mol of H₂S requires - 1/2 x 0.24 = 0.12 mol of SO₂ 
But 0.188 mol of SO₂ is present therefore SO₂ is in excess and H₂S is the limiting reactant.
H₂S is the limiting reactant
Amount of S produced depends on amount of H₂S present
Stoichiometry of H₂S to S is 2:3
2 mol of H₂S forms 3 mol of S
Therefore 0.24 mol of H₂S forms - 3/2 x 0.24 mol = 0.36 mol of S
Mass of S produced = 0.36 mol x 32 g/mol = 11.5 g of S is produced
7 0
3 years ago
A sentence with the word atom
Sati [7]

Answer:

we use atom in our sentences all the time

Explanation:

that what i put

8 0
3 years ago
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