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melamori03 [73]
3 years ago
7

The number of electrons in an oxide ion O^2- is?

Chemistry
1 answer:
Tatiana [17]3 years ago
7 0

10 electrons are in o^2

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Aldo cannot get the answer to a chemistry problem, even after sitting at his desk for an hour. He gets up and goes for a walk. S
Alex17521 [72]

Answer:

Insight

Explanation:

Insight is the understanding of a specific cause and effect within a specific context. The term insight can have several related meanings:

  • a piece of information
  • the act or result of understanding the inner nature of things or of seeing intuitively (called noesis in Greek)
  • an introspection
  • the power of acute observation and deduction, discernment, and perception, called intellection or noesis
  • an understanding of cause and effect based on identification of relationships and behaviors within a model, context, or scenario (see artificial intelligence)

An insight that manifests itself suddenly, such as understanding how to solve a difficult problem, is sometimes called by the German word Aha-Erlebnis. The term was coined by the German psychologist and theoretical linguist Karl Bühler. It is also known as an epiphany, eureka moment or (for cross word solvers) the penny dropping moment (PDM). Sudden sickening realizations identifying a problem rather than solving it, so Uh-oh rather than Aha moments are further seen in negative insight. A further example of negative insight is chagrin which is annoyance at the obviousness of a solution missed up until the point of insight.

6 0
3 years ago
HELP!!!! ASAP!!!!!!!!!!<br><br> HOW ARE REACTANTS DIFFERENT FROM THE PRODUCTS ?
raketka [301]
Reactants are what make up the product.
7 0
3 years ago
Read 2 more answers
scandium47 has a half-life of 35s. suppose you have a 45g sample of scadium 47 how much of the sample remains unchanged after 14
Mars2501 [29]

 The much  of the sample that would remain  unchanged  after 140 seconds is 2.813 g

Explanation

Half life  is time taken for the quantity  to reduce  to half its original value.

if the half life  for Scandium  is 35 sec, then the number  of half life in 140 seconds

=140 sec/ 35 s = 4 half life

Therefore 45 g after first half life = 45 x1/2 =22.5 g

               22.5 g after second half life = 22.5 x 1/2 =11.25 g

            11.25 g after third half life = 11.25 x 1/2 = 5.625 g

             5.625 after  fourth half life = 5.625 x 1/2 = 2.813

therefore 2.813 g  of Scandium 47 remains  unchanged.

4 0
2 years ago
how does an airplane’s kinetic energy and potential energy change as it takes off and lands? How does this energy change relate
mojhsa [17]

Answer: As the airplane goes higher, the mechanical energy is changed into gravitational potential energy. While flying, some energy is lost through drag to thermal (heat) energy and sound energy. Some is also lost as the plane makes the air around it move. ... As speed and height decrease, kinetic and potential energy decrease.

Explanation:

Hope this help

8 0
3 years ago
At equilibrium, the concentrations of the products and reactants for the reaction, H2 (g) + I2 (g)  2 HI (g), are [H2] = 0.106
lana [24]

Answer:

The new equilibrium concentration of HI: <u>[HI] = 3.589 M</u>          

Explanation:

Given: Initial concentrations at original equilibrium- [H₂] = 0.106 M; [I₂] = 0.022 M; [HI] = 1.29 M        

Final concentrations at new equilibrium- [H₂] = 0.95 M; [I₂] = 0.019 M; [HI] = ? M

<em>Given chemical reaction:</em> H₂(g) + I₂(g) → 2 HI(g)

The equilibrium constant (K_{c}) for the given chemical reaction, is given by the equation:

K_{c} = \frac {[HI]^{2}}{[H_{2}]\: [I_{2}]}

<u><em>At the original equilibrium state:</em></u>

K_{c} = \frac {(1.29\: M)^{2}}{(0.106\: M) \times (0.022\: M)}

K_{c} = \frac {1.6641}{0.002332} = 713.59

<u><em>Therefore, at the new equilibrium state:</em></u>

K_{c} = \frac {[HI]^{2}}{(0.95\: M) \times (0.019\: M)}

\Rightarrow K_{c} = 713.59 = \frac {[HI]^{2}}{0.01805}

\Rightarrow [HI]^{2} = 713.59 \times 0.01805 = 12.88

\Rightarrow [HI] = \sqrt {12.88} = 3.589 M

<u>Therefore, the new equilibrium concentration of HI: [HI] = 3.589 M</u>

6 0
2 years ago
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