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3 years ago

The number of electrons in an oxide ion O^2- is?

Chemistry

1 answer:

Tatiana [17]3 years ago

7 0

10 electrons are in o^2

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A student mixes some sugar into a cup of hot water. The sugar dissolves in the liquid. What are the BEST ways for the student to

polet [3.4K]

You would have to evaporate the water to get just the sugar

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3 years ago

Consider two concentric spheres whose radii differ by t = 1 nm, the "thickness" of the interface. At what radius (in nm) of sphe

Gala2k [10]

Answer:

Radius of the interior sphere = 3.847 nm

Explanation:

The volume of the shell (Vs) is equal to the difference of the volume of the outer sphere (Vo) and the volume of the inner sphere (Vi). Then:

$V_s=V_o-V_i=V_i\\V_o=2*V_i\\$

If we express the radius of the outer sphere (ro) in function of the radius of the inner sphere (ri), we have (e being the shell thickness):

$r_o=r_i+e$

The first equation becomes

$\frac{4 \pi}{3}*r_o^{3} = 2 * \frac{4 \pi}{3}*r_i^{3} \\\\\frac{4 \pi}{3}*(r_i+e)^{3} = 2 * \frac{4 \pi}{3}*r_i^{3} \\\\(r_i+e)^{3} = 2 *r_i^{3} \\\\(r_i^{3}+3r_i^{2}e+3r_ie^{2}+e^{3})=2r_i^{3}\\\\-r_i^{3}+3r_i^{2}e+3r_ie^{2}+e^{3}=0\\\\-r_i^{3}+3r_i^{2}+3r_i+1=0$

To find ri that satisfies this equation we have to find the roots of the polynomial.

Numerically, it could be calculated that ri=3.847 nm satisfies the equation.

So if the radius of the interior sphere is 3.847 nm, the volume of the interior sphere is equal to the volume of the shell of 1nm.

8 0

3 years ago

How does the human body keep warm on a cold day?

Margarita [4]

By wearing thick clothes, near in a furnace or something that is warm

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3 years ago

How many moles of lithium hydroxide are required to react with 19.2 mol CO2, the average amount exhaled by a person each day?

sladkih [1.3K]

Answer:

38.4 mol LiOH

Explanation:

Step 1: Write the balanced neutralization equation

2 LiOH + CO₂ ⇒ Li₂CO₃ + H₂O

Step 2: Establish the appropriate molar ratio

According to the balanced equation, the molar ratio of LiOH to CO₂ is 2:1.

Step 3: Calculate how many moles of lithium hydroxide are required to react with 19.2 mol CO₂

19.2 mol CO₂ × 2 mol LiOH / 1 mol CO₂ = 38.4 mol LiOH

3 0

3 years ago

There are (how many?) significant figures in: 0.0050110400

DanielleElmas [232]

I want to say 8 but i'm not sure. I just did a lesson on this and my notes say it could be 8 but then again I'm not sure.

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3 years ago