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Katena32 [7]
2 years ago
7

Solve the equation: |2x + 5| = 11.

Mathematics
2 answers:
MrRa [10]2 years ago
7 0

Answer:

x=3 or x= -8

Step-by-step explanation:

VladimirAG [237]2 years ago
5 0

Answer:

x = -8 and x = 3

Step-by-step explanation:

Split the equation into 2 possible cases:

2x + 5 = 11

2x + 5 = -11

Then, solve these 2 equations.

2x + 5 = 11

2x = 6

x = 3

2x + 5 = -11

2x = -16

x = -8

So, the 2 solutions are x = -8 and x = 3

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A new electric car uses 7.3% of its battery to drive 6.4 miles, at that rate how many miles can you drive using 100% of the batt
Natali [406]

Answer:

83.2 miles

Step-by-step explanation:

what i had to do was multiply 7.3 by 13 and that was 94.9 that was as close as i could get it to 100 so i then multipled 6.4 by 13 and got 83,2 miles

5 0
2 years ago
Place these events on the probability
Aleksandr [31]

Answer:

  • P(tails)=1/2
  • P(5)=1/6

Not sure of the rest but hope this helps

8 0
3 years ago
Fill in the bubble for the correct answer choice.
dalvyx [7]
She arrived to school at 8:08
8 0
3 years ago
PLEASE PLEASE HELP WITH MATH. ILL GIVE POINTS, BRAINLY AND FRIEND.
aleksley [76]

Answer:

∠BIJ ≅ ∠CGJ and ∠BJI ≅ ∠CJG

Step-by-step explanation:

We have that the initial triangles are equal. Let us check which components remain within the final triangles as the same. The only such components are the angles B and C. We now know that we have to apply a triangle equality criterion.

The triangles BGH and CIH are equal since the have 2 common sides and the respective interior angles are equal. Then we have that BI=GC and also that the respective angles  B and C are equal. THen also HIJ=HGJ since they fill to 180 degrees with angles that are equal.

Hence by angle-side-angle the triangles BJI and CJG are equal.

∠BIJ ≅ ∠CGJ and ∠BJI ≅ ∠CJG

8 0
2 years ago
Please help with 3. 4. 5.
Eddi Din [679]
3.
\text{The Triangle Sum Theorem:}\\m\angle A+m\angle B+m\angle C=180^o
x+2x-1+3x+1=180\\6x=180\ \ \ |:6\\x=30
x^o=30^o\\(3x+1)^o=(3\cdot30+1)^o=91^o\\(2x-1)^o=(2\cdot30-1)^o=59^o
4.
r-6+3r-3+5r=180\\9r-9=180\ \ \ |+9\\9r=189\ \ \ |:9\\r=21
(r-6)^o=(21-6)^o=15^o\\(3r-3)^o=(3\cdot21-3)^o=60^o\\(5r)^o=(5\cdot21)^o=105^o
5.
\text{The Exterior Angle Theorem:}\\m\angle CAB+m\angle ABC=m\angle DCB
2g+9g=110\\11g=110\ \ \ |:11\\g=10
m\angle A=2\cdot10^o=20^o\\m\angle ACB=180^o-110^o=70^o\\m\angle B=9\cdot10^o=90^o
4 0
3 years ago
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