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Rzqust [24]
4 years ago
10

My Everest is the highest mountain on earth.its height is 8.848 km. Convert this height to feet. Write your answer in standard n

umber format and using scientific notation
Chemistry
1 answer:
Vinvika [58]4 years ago
3 0

Answer: 2.9(10)^{7} ft

Explanation:

Firstly we need to know that 1 km=3280.84 ft, then we cam make the conversion:

8848 km \frac{3280.84 ft}{1 km}=29,028,872.32 ft This is the height of Mount Everest in feet

However, we can express it using scientific notation by counting to the left the decimal spaces:

29,028,872.32 ft \approx 2.9(10)^{7} ft

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How many moles of ammonla are produced by 2.8 mol of hydrogen.<br><br>ANH​
yan [13]

Answer:

3 i think

Explanation:

6 0
3 years ago
Thermal energy added to a substance that is not changing state causes the substance’s temperature to
tatyana61 [14]

Answer:

increase

Explanation:

Conduction involves the transfer of electric charge or thermal energy due to the movement of particles. When the conduction relates to electric charge, it is known as electrical conduction while when it relates to thermal energy, it is known as heat conduction. Conductors include metal, steel, aluminum, copper, frying pan, pot, spoon etc.

In the process of heat conduction, thermal energy is usually transferred from fast moving particles to slow moving particles during the collision of these particles. Also, thermal energy is typically transferred between objects that has different degrees of temperature and materials (particles) that are directly in contact with each other but differ in their ability to accept or give up electrons.

Hence, thermal energy added to a substance that is not changing state causes the substance’s temperature to increase because it would absorb energy in the form of heat.

6 0
3 years ago
A student wishes to calculate the experimental value of Ksp for AgI. S/he follows the procedure in Part 3 and finds Ecell to be
Ymorist [56]

Answer:

a)    [Ag+]dilute = 6.363  × 10⁻¹⁶ M  

b)    1.273 × 10⁻¹⁶

c)    2.629×10⁻¹⁹ M Thus; the value for  [Ag+ ]dilute will be too low

Explanation:

In an Ag | Ag+ concentration cell ,

The  anode reaction can be written as :

Ag ----> Ag+(dilute) + e-    &:

The  cathode reaction can be written as:

Ag+(concentrated) + e- ----> Ag

The  Overall Reaction : is

Ag+(concentrated) -----> Ag+(dilute)

However, the Standard Reduction potential of cell = E°cell = 0

( since both cathode and anode have same Ag+║Ag )

Also , given that the theoretical slope is - 0.0591 V

Therefore; the reduction potential of cell ; i.e

Ecell = E°cell - 0.0591 V × log ( [Ag+]dilute / [Ag+]concentrated )

0.839 V = 0 - 0.0591 V × log ( [Ag+]dilute / ( 1.0 × 10⁻¹ M ) )  

log ( [Ag+]dilute / ( 1.0 × 10⁻¹ M ) ) = - 14.1963  

[Ag+]dilute = \mathbf{10^{-14.1963} } × 1.0 × 10⁻¹ M

[Ag+]dilute = 6.363  × 10⁻¹⁶ M  

b)

AgI ----> Ag + (dilute) + I⁻

So , Solubility product = Ksp = [Ag⁺]dilute × [I⁻]  

= 6.363 × 10⁻¹⁶ M × 0.20 M  

= 1.273 × 10⁻¹⁶

c) If s/he mistakenly uses 1.039 V as Ecell; then the value for [Ag+]dilute will be :

Ecell = E°cell - 0.0591 V × log ( [Ag+]dilute / [Ag+]concentrated )

1.039 V = 0 - 0.0591 V × log ( [Ag+]dilute / ( 1.0 × 10⁻¹ M ) )  

log ( [Ag+]dilute / ( 1.0 × 10⁻¹ M ) ) = - 17.5804  

[Ag+]dilute = \mathbf{10^{-17.5804} } × 1.0 × 10⁻¹ M

[Ag+]dilute = 2.629×10⁻¹⁹ M

Thus, the value for  [Ag+ ]dilute will be too low

5 0
3 years ago
What is the classification of a solution of naoh with a ph of 8.3?
Maksim231197 [3]

Answer:

  • <u>Alkaline or basic solution </u>(alkaline and basic means the same)

Explanation:

According to the <em>pH</em>,  solutions may be classified as neutral, acidic, or alkaline (basic).

This table shows such classification:

pH               classification

  7                   neutral

> 7                   alkaline or basic

< 7                   acidic

Thus, since the pH of the solution is 8.3, which is greater than 7, the solution is classified as basic (alkaline).

Additionally, you must learn that pH is a logarithmic scale for the concentration of hydronium ions in the solution.

  • pH = - log [H₃O⁺]

You can calculate the concentration of hydronium ions using antilogarithm properties:

pH=-log[H_3O^+]\\ \\ {[H_3O^+]}=10^{-pH}\\ \\ {[H_3O^+]}=10^{-8.3}=0.00000000501

NaOH solutions are alkaline solutions, bases, according to Arrhenius model,  because they contain OH⁻ ions and release them when ionize in water.

8 0
3 years ago
What did the professer use a catalyst for the flubber experiment
Anettt [7]
In the 1997 movie called, Flubber, the professor used an organic catalyst and a little touch of electricity to make flubber. The organic substance is not known.
Thank you for posting your question here at brainly. I hope the answer helps.
7 0
3 years ago
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