Answer:
Sure I'll help you!
Explanation:
The head of the nail is flat and isn't sharp enough to cut anything, If you stab someone with a sword then hit them with a shield would it have the same effect? Of course not.
Answer:
Thus there was no accumulation of ions on the nails, as the dissolved gases were already removed, hence no rust formation. In test tube C, a chemical was added to absorb the water vapour. We know that rust formation takes place when a metal is exposed to water vapour.
Explanation:i hope u have a wonderful night and stays safe
Answer:
3) Neither created nor destroyed. Only converted.
Explanation:
Okay so,
1) Translation- show the RNA strand attatching to a DNA strand with the complimentary base pairs. introns are spliced
2) mRNA leaves the cell and joins with a ribosome
3) Transcription - tRNA (clover shaped) reads each codon (triplets) which each code for an amino acid. The stop codons on the end tell the tRNA that the chain is finished
4) the sequence forms the primary structure (all peptide bonds) which determines the shape of the secondary (hyrdogen and peptide) and hence determines the shape of the tertiary structure of a protein (ionic, hydrogen, disulfide bridges and hydrophibic interactions)
Hope this helps :)
Answer:
B. A precipitate will form since Q > Ksp for calcium oxalate
Explanation:
Ksp of CaC₂O₄ is:
CaC₂O₄(s) ⇄ Ca²⁺ + C₂O₄²⁻
Where Ksp is defined as the product of concentrations of Ca²⁺ and C₂O₄²⁻ in equilibrium:
Ksp = [Ca²⁺][C₂O₄²⁻] = 2.27x10⁻⁹
In the solution, the concentration of calcium ion is 3.5x10⁻⁴M and concentration of oxalate ion is 2.33x10⁻⁴M.
Replacing in Ksp formula:
[3.5x10⁻⁴M][2.33x10⁻⁴M] = 8.155x10⁻⁸. This value is reaction quotient, Q.
If Q is higher than Ksp, the ions will produce the precipitate CaC₂O₄ until [Ca²⁺][C₂O₄²⁻] = Ksp.
Thus, right answer is:
<em>B. A precipitate will form since Q > Ksp for calcium oxalate</em>
<em></em>
