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Musya8 [376]
3 years ago
12

Help with all of these please!

Chemistry
1 answer:
Dovator [93]3 years ago
3 0

Answer:

Is that chemistry ??? Goodnight

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What was johann dobereiner contribution to the periodic table
k0ka [10]

Answer:

he introduced triads of similar chemical properties in periodic table.

Explanation:

3 0
3 years ago
Calculate the number of hydrogen atoms in a 110.0 sample of tetraborane(B4H10) . Be sure your answer has a unit symbol if necess
Contact [7]

Answer:

1.242 \times 10^{25}\text{ atoms H}

Explanation:

You must convert the mass of B₄H₁₀ to moles of B₄H₁₀, then to molecules of B₄H₁₀, and finally to atoms of H.

1. Moles of B₄H₁₀

\text{Moles of B$_{4}$H}_{10} = \text{110.0 g B$_{4}$H}_{10} \times \dfrac{\text{1 mol B$_{4}$H}_{10}}{\text{53.32 g B$_{4}$H}_{10}} = \text{2.063 mol B$_{4}$H}_{10}

2. Molecules of B₄H₁₀

\text{No. of molecules} = \text{2.063 mol B$_{4}$H}_{10} \times \dfrac{6.022 \times 10^{23}\text{ molecules B$_{4}$H}_{10}}{\text{1 mol B$_{4}$H}_{10}}\\\\=1.242 \times 10^{24}\text{ molecules B$_{4}$H}_{10}

3. Atoms of H

\text{Atoms of H} = 1.242 \times 10^{24}\text{ molecules B$_{4}$H}_{10} \times \dfrac{\text{10 atoms H}}{\text{1 molecule B$_{4}$H}_{10}}\\\\= \mathbf{1.242 \times 10^{25}}\textbf{ atoms H}

8 0
3 years ago
A runner wants to run 13.1 km . She knows that her running pace is 6.2 mi/h .How many minutes must she run? Hint: Use 6.2 mi/h a
frutty [35]

Answer:

  • <u>79 minutes</u>

Explanation:

1)<u> Convert the distance, 13.1 km to miles</u>

  • Conversion factor:

        1 = 1 mi / 1.61 km

  • 13.1 km [ 1 mi /  1.61 km ] = 8.1336 mi

2)<u> Use 6.2 mi/h as a converstion factor between distance and time</u>

  • 8.1366 mi × 1 / [6.2 mi/h] = 1.3124 h

3) <u>Convert 1.3124 h to minutes</u>

  • 1.3124 h × [ 60 min/h] = 78.7 min

Rounding to the nearest minutes (two significant figures):

  • 79 min ← answer
4 0
3 years ago
If the solvent is a liquid, then the solute:
Lelechka [254]

Answer:

must be either a gas or liquid

8 0
3 years ago
PLEASE HELP DUE TODAY 55 POINTS
Dvinal [7]

Answer : The final volume of gas will be, 26.3 mL

Explanation :

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas = 0.974 atm

P_2 = final pressure of gas = 0.993 atm

V_1 = initial volume of gas = 27.5 mL

V_2 = final volume of gas = ?

T_1 = initial temperature of gas = 22.0^oC=273+22.0=295K

T_2 = final temperature of gas = 15.0^oC=273+15.0=288K

Now put all the given values in the above equation, we get:

\frac{0.974 atm\times 27.5 mL}{295K}=\frac{0.993 atm\times V_2}{288K}

V_2=26.3mL

Therefore, the final volume of gas will be, 26.3 mL

3 0
3 years ago
Read 2 more answers
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