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laila [671]
3 years ago
6

All molecular motion stops at 0 on this scale

Chemistry
2 answers:
Oxana [17]3 years ago
4 0
Kelvin Hope this helps
maxonik [38]3 years ago
4 0
The answer is Kelvin
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Using the following equation for the combustion of octane calculate the heat associated with the formation of 100.0 g of carbon
natali 33 [55]

Answer:

The right solution is "-602.69 KJ heat".

Explanation:

According to the question,

The 100.0 g of carbon dioxide:

= \frac{100.0 \ g}{114.33\  g/mole}

= 0.8747 \ moles

We know that 16 moles of CO_2 formation associates with -11018 kJ of heat, then

0.8747 moles CO_2 formation associates with,

= -\frac{0.8747}{16}\times 11018 \ KJ \ of \ heat

= -0.0547\times 11018

= -602.69 \ KJ \ heat

8 0
3 years ago
Would you expect Nio to dissolve in an aqueous solution of NaNO3?
Doss [256]

Answer:

NiO Does Not Dissolve In An Aqueous Solution Of NaNO3.

Explanation:

6 0
3 years ago
What is true about an element
stich3 [128]

Answer:

made from ine atom

Explanation:

one atom

5 0
3 years ago
Specific Heat Practice
Alexxx [7]

Answer:

See below

Explanation:

<u>Specific Heat of water</u> =  4.186 J/(g-C)

J/(g-C)     multiplied  by  g   and C   results in J

4.186  * 540  * (95-32) = <u>142 407 .72 J</u>

3 0
2 years ago
Suppose of hcl and of o2 are added to an empty flask. How much will be in the flask at equilibrium?A. None. B. Some, but less th
serg [7]

This is an incomplete question, here is a complete question.

Hydrogen chloride and oxygen react to form water and chlorine, like this:

4HCI(g)+O_2(g)\rightarrow 2H_2(g)+2CI_2(g)

Use this chemical equation to answer the questions in the table below.

Suppose 155. mmol of HCl and 38.8 mmol of O₂ are added to an empty flask. How much HCl will be in the flask at equilibrium?

(1) None.

(2) Some, but less than 155. mmol,

(3) 155. mmol,

(4) More than 155. mmol,

Answer : The correct option is, (1) None

Explanation :

The given balanced chemical reaction is:

4HCI(g)+O_2(g)\rightarrow 2H_2(g)+2CI_2(g)

From the balanced chemical reaction, we conclude that

As, 4 mmole of HCl react with 1 mmoles of O_2

So, 155. mmole of HCl react with \frac{155.}{4}\times 1=38.75 mmoles of O_2

That means, O_2 is excess reagent and HCl is a limiting reagent. All the moles of HCl will consume.

Hence, the correct option is, None.

7 0
3 years ago
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