Oxidation state of I is (-1) and for CO it is zero. Let's assume that the oxidation state of Fe in Fe(CO)₄I₂<span> (s) is x. For whole compound, the charge is zero.
Sum of oxidation numbers in all elements = Charge of the compound.
Here we have 1Fe , 4CO and 2I
hence we can find the oxidation state as;
x + 4*0 + 2*(-1) = 0
x + 0 - 2 = 0
x = +2
Hence the oxidation state of Fe in product </span>Fe(CO)₄I₂ (s) is +2.
Same as we can find the oxidation state (y) of Fe in Fe(CO)₅(s).
y + 5*0 = 0
y = 0
Since oxidation state of Fe increased from 0 to +2, the oxidized element is Fe in the given reaction.
I suppose it would be forest because in order to have organic matter the soil needs to be rich and fertile,therefore it is forest.
Ionic and covalent bonds are both strong intermolecular forces. They are generally both crystalline in structure. But relatively speaking, ionic bonds are much stronger. As a consequence, they have inherent properties of higher boiling points, higher melting points, lower volatility, etc. Also, ionic bonds display conductive properties because they are strong electrolytes. <em>Thus, the answer is 5) higher melting points.</em>
Answer:
When an electron is hit by a photon of light, it absorbs the quanta of energy the photon was carrying and moves to a higher energy state. One way of thinking about this higher energy state is to imagine that the electron is now moving faster, (it has just been "hit" by a rapidly moving photon).
Explanation: pls mark brainliest :))
Answer:
It's simpler than most questions :)
Explanation:
1) B
2) B
3) D
4) A
5) A
Hope this will help :)
