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Sphinxa [80]
3 years ago
5

A trumpet creates a sound wave that has a wave speed of 350m/s and a wavelength of 0.8 m . What is the frequency of the sound wa

ve
Physics
1 answer:
ValentinkaMS [17]3 years ago
7 0

Answer:

The frequency of sound wave created by trumpet is 437.5Hz

Explanation:

Given

the speed of sound wave = 350 ms^{-1}

the wavelength of sound wave = 0.8 m

the frequency of sound wave = ?

All the waves have same relationship among wavelength, frequency and speed, which is given by the equation:

v = fλ, where

v is speed of the wave

f is frequency of the wave

λ is wavelength of the wave

therefore frequency of sound wave is given by

f = v/λ

 = 350ms^{-1}/0.8m

 = 437.5s^{-1}

 = 437.5Hz (since 1 s^{-1} = 1 Hz (Hertz)

Hence the frequency of sound wave created by trumpet is 437.5Hz

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9.8 Joules (rounded to 2 significant figures)

Explanation:

Work done (J)= Force(N) x distance changed (m)

  • Force= 9.80665 x 0.5kg
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  • Distance changed= 5-3
  • distance changed= 2m/s

--> work done= 4.90332 x 2

work done= 9.8 Joules

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3.7 kN (Up)

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Friction provides the force needed for a car to travel around a flat, circular race track. What is the maximum speed at which a
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The maximum speed at which the car can safety travel around the track is 18.6m/s.

Explanation:

Since the car is in circular motion, there has to be a centripetal force F_c. In this case, the only force that applies for that is the static frictional force f_sbetween the tires and the track. Then, we can write that:

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And since f_s\leq \mu N and F_c=\frac{mv^{2}}{r}, we have:

\mu N\geq \frac{mv^{2}}{r}

Now, if we write the vertical equation of motion of the car (in which there are only the weight and the normal force), we obtain:

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Substituting this expression for N and solving for v, we get:

\mu mg\geq \frac{mv^{2}}{r}\\\\v\leq \sqrt{\mu gr}

Finally, plugging in the given values for the coefficient of friction and the radius of the track, we have:

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