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Sphinxa [80]
3 years ago
5

A trumpet creates a sound wave that has a wave speed of 350m/s and a wavelength of 0.8 m . What is the frequency of the sound wa

ve
Physics
1 answer:
ValentinkaMS [17]3 years ago
7 0

Answer:

The frequency of sound wave created by trumpet is 437.5Hz

Explanation:

Given

the speed of sound wave = 350 ms^{-1}

the wavelength of sound wave = 0.8 m

the frequency of sound wave = ?

All the waves have same relationship among wavelength, frequency and speed, which is given by the equation:

v = fλ, where

v is speed of the wave

f is frequency of the wave

λ is wavelength of the wave

therefore frequency of sound wave is given by

f = v/λ

 = 350ms^{-1}/0.8m

 = 437.5s^{-1}

 = 437.5Hz (since 1 s^{-1} = 1 Hz (Hertz)

Hence the frequency of sound wave created by trumpet is 437.5Hz

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According to Lenz's law, the induced current in a circuit always flows to oppose the external magnetic field through the circuit
Makovka662 [10]

Answer:

True.

Explanation:

According to Lenz's law, the induced current in a circuit always flows to oppose the external magnetic field through the circuit. This statement is true.

The Faraday's law of induction is given by :

\epsilon=-\dfrac{d\phi}{dt}

Here, negative sign shows that the direction of induced emf is such that opposes the changing current that is its cause.

Hence, the statement is true.

3 0
3 years ago
"Determine the magnitude of the net force of gravity acting on the Moon during an eclipse when it is directly between Earth and
spayn [35]

Answer:

Net force = 2.3686 × 10^(20) N

Explanation:

To solve this, we have to find the force of the earth acting on the moon and the force of the sun acting on the moon and find the difference.

Now, from standards;

Mass of earth;M_e = 5.98 × 10^(24) kg

Mass of moon;M_m = 7.36 × 10^(22) kg

Mass of sun;M_s = 1.99 × 10^(30) kg

Distance between the sun and earth;d_se = 1.5 × 10^(11) m

Distance between moon and earth;d_em = 3.84 × 10^(8) m

Distance between sun and moon;d_sm = (1.5 × 10^(11)) - (3.84 × 10^(8)) = 1496.96 × 10^(8) m

Gravitational constant;G = 6.67 × 10^(-11) Nm²/kg²

Now formula for gravitational force between the earth and the moon is;

F_em = (G × M_e × M_m)/(d_em)²

Plugging in relevant values, we have;

F_em = (6.67 × 10^(-11) × 5.98 × 10^(24) × 7.36 × 10^(22))/(3.84 × 10^(8))²

F_em = 1.9909 × 10^(20) N

Similarly, formula for gravitational force between the sun and moon is;

F_sm = (G × M_s × M_m)/(d_sm)²

Plugging in relevant values, we have;

F_se = (6.67 × 10^(-11) × 1.99 × 10^(30) ×

7.36 × 10^(22))/(1496.96 × 10^(8))²

F_se = 4.3595 × 10^(20) N

Thus, net force = F_se - F_em

Net force = (4.3595 × 10^(20) N) - (1.9909 × 10^(20) N) = 2.3686 × 10^(20) N

8 0
3 years ago
Kristen has two identical sized cubes, one is lead (Pb) and one is copper (Cu). Kristen is determining the density of each cube.
natta225 [31]

Answer:

volume

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2 years ago
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A laser beam, shining from the earth's surface, is directed at the moon whose distance from the earth on this day is 370,000 km.
nekit [7.7K]

Answer:

d = 6105 m

Explanation:

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let's use the tangent

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let's be careful since the angles are in radians

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This is the distance from the normal that corresponds to the radius of the circle, the diameter is twice the radius

          d = 2 y

          d = 2 3025.5

          d = 6105 m

6 0
2 years ago
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