The answer to this question is false. 
        
                    
             
        
        
        
The distance travelled by the object during the first 4 seconds is 80 m
<h3>Definition of speed </h3>
Speed is defined as the distance travelled per unit time. Mathematically, it can be expressed as:
Speed = distance / time 
With the above formula, we can obtain the distance travelled by the object in the first 4 seconds. 
<h3>How to determine the distance travelled </h3>
Speed = distance / time 
20 = distance / 4
Cross multiply 
Distance = 20 × 4
Distance = 80 m 
Complete question:
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Learn more about speed:
brainly.com/question/680492
 
        
             
        
        
        
Answer:
47 m
Explanation:
Data obtained from the question include the following:
Length of dry leg 1 (L1) = 40 m
Length of dry leg 2 (L2) = 25 m
Length of swimming course (L) =..?
The length of the swimming course can be obtained by using pythagoras theory as shown below:
L² = L1² + L2²
L² = 40² + 25²
L² = 1600 + 625
L² = 2225
Take the square root of both side. 
L = √2225
L = 47.1 ≈ 47 m
Therefore, the length of the swimming course is approximately 47 m. 
 
        
             
        
        
        
Answer:
2.145×10^-10 V or 0.2145nV
Explanation:
From hf=eV
h= Plank's constant = 6.6×10^-34JS
f= frequency of the electromagnetic wave = 5.2×10^4 Hz
e= electronic charge= 1.6×10^-19 C
V= voltage
V= hf/e
V= 6.6×10^-34JS × 5.2×10^4 Hz/ 1.6×10^-19 C
V= 2.145×10^-10 V or 0.2145nV
Therefore the voltage created is 2.145×10^-10 V or 0.2145nV
 
        
             
        
        
        
Answer:
<em>The period of the motion will still be equal to T.</em>
<em></em>
Explanation:
for a system with mass = M
attached to a massless spring.
If the system is set in motion with an amplitude (distance from equilibrium position) A
and has period T
The equation for the period T is given as

where k is the spring constant
If the amplitude is doubled, the distance from equilibrium position to the displacement is doubled.
Increasing the amplitude also increases the restoring force. An increase in the restoring force means the mass is now accelerated to cover more distance in the same period, so the restoring force cancels the effect of the increase in amplitude. Hence, <em>increasing the amplitude has no effect on the period of the mass and spring system.</em>