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olga_2 [115]
4 years ago
10

A particular bird’s eye can just distinguish objects that subtend an angle no smaller than about 4.0x10^-4 rads.

Physics
1 answer:
allsm [11]4 years ago
7 0

Answer:

Part a)

Angle in degree is given as

\theta = 0.023 ^o

Part b)

Size of the object is

Length = 0.064 m

Explanation:

Part a)

As we know that

180 degree = \pi radian

so we have

\theta = 4.0 \times 10^{-4} rad

so we have

\theta = 4.0 \times 10^{-4} \times \frac{180}{\pi}

\theta = 0.023 ^o

Part b)

As we know that the relation of angle with radius is

\theta = \frac{arc}{radius}

4 \times 10^{-4} = \frac{Length}{160}

Length = 0.064 m

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A plant is thrown straight
olchik [2.2K]

The time taken for the plant to hit the ground from a distance of 7.01m and at a velocity of 8.84m/s is 1.59s.

<h3>How to calculate time?</h3>

The time taken for a motion to occur can be calculated using the following formula:

v² = u² - 2as

Where;

  • v = final velocity
  • u = initial velocity
  • s = distance
  • a = acceleration

8.84² = 0² + 2 × a × 7.01

78.15 = 14.02a

a = 5.57m/s²

V = u + at

8.84 = 0 + 5.57t

t = 1.59s

Therefore, the time taken for the plant to hit the ground from a distance of 7.01m and at a velocity of 8.84m/s is 1.59s.

Learn more about time at: brainly.com/question/13170991

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4 0
2 years ago
Two blocks A and B have a weight of 11 lb and 6 lb, respectively. They are resting on the incline for which the coefficients of
Andreas93 [3]

Answer:

the block that starts moving first is block A ,    fr = 1.625 N ,  fr = 1.5 N

Explanation:

For this exercise we use Newton's second law, for which we take a reference system with the x axis parallel to the plane and the y axis perpendicular to the plane

X axis

       fr- Wₓ = 0

       fr = Wₓ

Axis y

      N- W_{y} = 0

      N = W_{y}

Let's use trigonometry to find the components of the weight

     sin θ = Wₓ / W

     Cos θ = W_{y} / W

     Wₓ = W sin θ

     W_{y} = W cos θ

     Wₓ = 11 sin θ

     W_{y} = 11 cos θ

The equation for friction force is

      fr = μ N

   

We substitute

      μ (W cos θ) = W sin θ

      μ = tan θ

We can see that the system began to move the angle.

         θ = tan⁻¹ μ

So the angles are

Block A      θ = tan⁻¹ 0.15

           θ = 8.5º

Block B      θ = tan⁻¹ 0.26

             θ = 14.6º

So the block that starts moving first is block A

The friction force is

         

Block A

         fr = Wx = W sin θ

         fr = 11 sin 8.5

         fr = 1.625 N

Block B

         fr = 6 sin 14.6

         fr = 1.5 N

5 0
4 years ago
An aluminum sphere is 8.55 cm in diameter. What will be it's % change in volume if it is heated from 30 C to 155 C?
Ghella [55]

We know that

• The sphere diameter is 8.55 cm.

,

• The temperature change is from 30 C to 155 C.

First, we have to find the radius of the sphere. The radius is the half diameter.

\begin{gathered} r=\frac{d}{2}=\frac{8.55\operatorname{cm}}{2} \\ r=4.275\operatorname{cm} \end{gathered}

Now we have to find the volume of the sphere using the following formula.

V=\frac{4}{3}\pi(r)^3

Where r = 4.275 cm.

\begin{gathered} V=\frac{4}{3}\pi(4.275\operatorname{cm})^3 \\ V\approx327.26(cm)^3 \end{gathered}

Then, we use the following formula

V_2-V_1=BV_0(T_2-T_1)

Where the initial volume is 327.26 cubic cm, B is a constant about thermal expansion for aluminum, and we have to find the final volume to then calculate the percentage change.

\begin{gathered} \Delta V=75\times10^{-6}\cdot327.26(155-30) \\ \Delta V=75\times10^{-6}\cdot327.26(125) \\ \Delta V\approx3.07(cm)^3 \end{gathered}

This means that the volume change is 3.07 cubic centimeters.

At last, we have to divide the volume change by the initial volume, and then we have to multiply it by 100% to express it as a percentage.

\frac{\Delta V}{V_1}\times100=\frac{3.07}{327.26}\times100\approx0.938<h2>Therefore, the percentage change is 0.938%.</h2>

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yaroslaw [1]

Answer:PV/T

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The formula for the combined gas law can be adjusted to compare two sets of conditions in one substance. P1V1 / T1 = P2V2 / T2

4 0
4 years ago
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