A balloon is a sphere with a radius of 5.0 m. the force of air against the walls of the balloon is 45 n. what is the air pressur
1 answer:
The air pressure inside the balloon is: 0.1432 Pa
The formulas and procedures that we will use to solve this problem are:
- a = 4 * π * r²
- P = F/a
Where:
- a = area of the sphere
- r = radius
- π = mathematical constant
- P = Pressure
- F = Force
- a = surface area
Information about the problem:
- r = 5.0 m
- F = 45 N
- 1 Pa = N/m²
- 1 N = kg * m/s²
- a=?
- P=?
Using the formula of the sphere area we get:
a = 4 * π * r²
a = 4 * 3.1416 * (5.0 m)²
a = 314.16 m²
Applying the pressure formula we get:
P = F/a
P = 45 N/314.16 m²
P = 0.1432 Pa
<h3>What is pressure?</h3>It is a physical quantity that expresses the force applied on the area of a surface.
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Answer:
1083.3kg/m ³
Explanation:
Given parameters:
Mass of aluminium ball = 3.4kg
Apparent mass of ball = 2.1kg
Unknown:
Density of the liquid = ?
Solution:
Density is is the mass per unit volume of any give substance;
Density =
Now, we must understand that the apparent weight of the aluminium is the part of its weight supported by the fluid;
Pl =
Pl = density of liquid
Ml = mass of liquid
Vl = volume of liquid
Mass of liquid = Mal - Mapparent
Mal = mass of aluminium
The volume of liquid displaced is the same as the volume of the aluminium according to Archimedes's principle;
Ml = Pl x Vl
Val = Vl
Val volume of aluminium
Vl = volume of liquid
****
Pal =
Val =
Val = volume of aluminium
Mal = mass of aluminium
Pal = density of aluminium
*****
Since the Val = Vl
Ml = Pl x
Since
Ml = Mal - Mapparent
Mal - Mapparent = Pl x
Pal = density of aluminium = 2712 kg/m ³
3.4 - 2.1 = Pl x
1.3 = Pl x 0.00123
Pl = 1083.3kg/m ³
Answer:
(I). The effective cross sectional area of the capillaries is 0.188 m².
(II). The approximate number of capillaries is
Explanation:
Given that,
Radius of aorta = 10 mm
Speed = 300 mm/s
Radius of capillary
Speed of blood
(I). We need to calculate the effective cross sectional area of the capillaries
Using continuity equation
Where. v₁ = speed of blood in capillarity
A₂ = area of cross section of aorta
v₂ =speed of blood in aorta
Put the value into the formula
(II). We need to calculate the approximate number of capillaries
Using formula of area of cross section
Put the value into the formula
Hence, (I). The effective cross sectional area of the capillaries is 0.188 m².
(II). The approximate number of capillaries is