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MaRussiya [10]
1 year ago
9

A balloon is a sphere with a radius of 5.0 m. the force of air against the walls of the balloon is 45 n. what is the air pressur

e inside the balloon?
Physics
1 answer:
Mazyrski [523]1 year ago
7 0

The air pressure inside the balloon is: 0.1432 Pa

The formulas and procedures that we will use to solve this problem are:

  • a = 4 * π * r²
  • P = F/a

Where:

  • a = area of the sphere
  • r = radius
  • π = mathematical constant
  • P = Pressure
  • F = Force
  • a = surface area

Information about the problem:

  • r = 5.0 m
  • F = 45 N
  • 1 Pa = N/m²
  • 1 N = kg * m/s²
  • a=?
  • P=?

Using the formula of the sphere area we get:

a = 4 * π * r²

a = 4 * 3.1416 * (5.0 m)²

a = 314.16 m²

Applying the pressure formula we get:

P = F/a

P = 45 N/314.16 m²

P = 0.1432 Pa

<h3>What is pressure?</h3>

It is a physical quantity that expresses the force applied on the area of a surface.

Learn more about pressure at: brainly.com/question/26269477

#SPJ4

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1. Frequency: 7.06\cdot 10^{14} Hz

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f=\frac{c}{\lambda}

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In this problem, we have light with wavelength

\lambda=425 nm=425\cdot 10^{-9} m

Substituting into the equation, we find the frequency:

f=\frac{c}{\lambda}=\frac{3\cdot 10^{-8} m/s}{425\cdot 10^{-9} m}=7.06\cdot 10^{14} Hz


2. Period: 1.42 \cdot 10^{-15}s

The period of a wave is equal to the reciprocal of the frequency:

T=\frac{1}{f}

The frequency of this light wave is 7.06\cdot 10^{14} Hz (found in the previous exercise), so the period is:

T=\frac{1}{f}=\frac{1}{7.06\cdot 10^{14} Hz}=1.42\cdot 10^{-15} s


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Who predict the black hole​
kramer

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An experimental tungsten light bulb filament has a length of 5 cm and a diameter of 0.074 cm. The filament is basically just a w
adell [148]

Answer:

power emitted is 1.75 W

Explanation:

given data

length l = 5 cm = 5 ×10^{-2} m

diameter d = 0.074 cm = 74 ×10^{-5} m

total filament emissivity = 0.300

temperature = 3068 K

to find out

power emitted

solution

we find first area that is π×d×L

area = π×d×L

area = π×74 ×10^{-5}×5 ×10^{-2}

area = 1162.3892  ×10^{-5} m²

so here power emitted  is express as

power emitted  = E × σ × area × (temperature)^4

put here all value

power emitted  = 0.300× 5.67 × 1162.3892  ×10^{-5}  × (3068)^4

power emitted = 1.75 W

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Travels 11,000 feet along a dark desert highway if the car averages 84 mph find the amount of time to cover this distance
laila [671]

The time taken by traveler to cover the distance is,

t=\frac{d}{v}

Substitute the known values,

\begin{gathered} t=\frac{(11000\text{ ft)}}{(84\text{ mph)(}\frac{1.46667\text{ ft/s}}{1\text{ mph}})_{}} \\ \approx89.3\text{ s} \end{gathered}

Therefore, the time taken by traveler to cover the distance is 89.3 s.

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