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JulijaS [17]
3 years ago
6

A horse is grazing for food. It trots rightward 15 m to eat a carrot, then walks rightward 20 m, to another carrot, then turns l

eftwards to walk 4m, to bite an apple. The horse walks a total time of 74 seconds. What is the magnitude of its average velocity?
(** HINT- you may want to draw this out, remember with VELOCITY direction matters-opposite vectors cancel out-with SPEED direction does not matter).
Physics
1 answer:
mafiozo [28]3 years ago
6 0

Answer:

<h3>0.42s</h3>

Explanation:

Velocity = Displacement/time

Displacement of the horse is the distance covered in a specified direction

Total distance of the horse towards the right = 15m + 20m = 35m

Total distance of the horse towards the left = 4m

Displacement = Distance towards the right - Distance towards the left

Displacement = 35m-4m

Displacement =  31m

Time taken = 74seconds

substitute the values gotten into the velocity formula

average velocity = 31m/74s

average velocity = 0.42m/s

Hence the magnitude of its average velocity is 0.42s

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A force of 10 newtons acts in a direction 75° above horizontal, moving an object 15 meters from (0, 0) to (15, 0). what is the w
hammer [34]

Work done by the force is 150 Joules.

Steps involved in the question:

Step one:

Given data

Force F= 10N

the distance is described by the coordinate =  (0,0) to (15,0)

hence the distance = 15m in the x-direction.

Step two:

Required is the work done

we know that work done is expressed as

Wd= Force* Distance

Wd= 10*15

Wd= 150 Joules

To learn more about work done refer : brainly.com/question/25573309

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6 0
2 years ago
A solid cylinder with a mass of 2.46 kg and a radius of 0.049 m starts from rest at a height of 4.80 m and rolls down a 24.3 ◦ s
irina1246 [14]

Answer:

v_{f}\approx 2.097\,\frac{m}{s}

Explanation:

Let assume that the solid cylinder rolls down a frictionless incline. The translational speed can be found by using the Principle of Energy Conservation and the Work-Energy Theorem:

m_{cyl}\cdot g\cdot y_{o} = \frac{1}{2}\cdot m_{cyl} \left( 1+ \frac{1}{R}\right)\cdot v_{f}^{2}

g\cdot y_{o} = \frac{1}{2}\cdot\left( 1+ \frac{1}{R}\right)\cdot v_{f}^{2}

The translational speed is:

v_{f} = \sqrt{\frac{2\cdot g\cdot y_{o}}{\left(1 + \frac{1}{R}  \right)}}

v_{f} = \sqrt{\frac{2\cdot (9.807\,\frac{m}{s^{2}} )\cdot (4.80\,m)}{\left(1 + \frac{1}{0.049\,m}  \right)} }

v_{f}\approx 2.097\,\frac{m}{s}

7 0
3 years ago
The transmission of heat requiring the movement of a liquid or a gas is A. conduction B. radiation. C. convection. D. transducti
Llana [10]

Answer:

convection C

Explanation:

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A solar prominence is
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B. a solar storm that moves across the sun's surface
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Read 2 more answers
If a wave vibrates up and down twice each second and travels a distance of 20 m each second and travels a distance of 20 m each
ivolga24 [154]

Answer:

Frequency is 0.5 Hz and the wave speed is 10 m/s.

Explanation:

As we know that frequency is defined as the how many times the no of cycles repeat in one second so if the wave is vibrating up and down  twice during 1 second then the frequency in 1 second is

f=\frac{1}{2} hz\\F=0.5hz

Therefore frequency is 0.5 Hz.

Now the distance of wawe in each second is,

d=20m

Now the wave velocity is,

v=fd

Here, f is frequency, d is the distance, v is the wave velocity.

Substitute all the variables

v=0.5\times 20\\v=10m/s

Therefore the wave speed is 10 m/s.

6 0
3 years ago
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