Question

A person is lifting a bag of groceries with a uniform force of 75.0 N upward for 2.50 s. They raised the bag 1.50 m to place on a table from the floor. What power did they use?​

Answer 1

Answer:

45 W

Explanation:

First of all, we need to find the work done by the person to lift the bag. The work done is given by

$W=Fd$

where

F = 75.0 N is the force applied

d = 1.50 m is the displacement of the bag

Substituting numbers into the formula,

$W=(75.0 N)(1.5 m)=112.5 J$

Now we can find the power used, which is given by

$P=\frac{W}{t}$

where

t = 2.50 s is the time taken

Again, using W=112.5 J, we find

$P=\frac{112.5 J}{2.5 s}=45 W$