Given:
(Initial velocity)u=20 m/s
At the maximum height the final velocity of the ball is 0.
Also since it is a free falling object the acceleration acting on the ball is due to gravity g.
Thus a=- 9.8 m/s^2
Now consider the equation
v^2-u^2= 2as
Where v is the final velocity which is measured in m/s
Where u is the initial velocity which is measured in m/s
a is the acceleration due to gravity measured in m/s^2
s is the displacement of the ball in this case it is the maximum height attained by the ball which is measured in m.
Substituting the given values in the above formula we get
0-(20x20)= 2 x- 9.8 x s
s= 400/19.6= 20.41m
Thus the maximum height attained is 20.41 m by the ball
We know that 1 minute= 60 seconds (or 1 min= 60 s).
10 min* (60 s/ 1 min)* (2.0 m/ 1 s)= 1,200 m.
(Note that the units cancel out so you get the answer)
The final answer is 1,200 m.
Hope this helps~
Answer:
A.
Explanation:
X represents the transmitting power Modulates (amplitude or frequency am/fm), amplifies the signal, transmitting it out at whatever direction the antenna is set up for.
Lysosomes are used by the cell to digest or breakdown multifaceted organic molecules
