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laiz [17]
4 years ago
5

A 35-gram stainless steel ball on a track is moving at a velocity of 9 m/s. On the same track, a 75-gram stainless steel ball is

moving at a velocity of –7 m/s. After colliding, the 35-gram ball moves at a velocity of –15 m/s. Assume there is no net force on the system. What is the velocity of the 75-gram ball after the collision? Round to the nearest tenth. –4.2 m/s –0.5 m/s 0.5 m/s 4.2 m/s
Physics
2 answers:
Serhud [2]4 years ago
7 0

Answer:

D. 4.2

Explanation:

On Edgenuity :)

elena-s [515]4 years ago
5 0

Answer:

4.2 m/s

Explanation:

Momentum is conserved.

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

(35 g) (9 m/s) + (75 g) (-7 m/s) = (35 g) (-15 m/s) + (75 g) v

315 g m/s − 525 g m/s = -525 g m/s + (75 g) v

315 g m/s = (75 g) v

v = 4.2 m/s

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Calculate the amount of heat needed to increase the temperature of 200 grams of water at 10°C to 95°C.
Alexus [3.1K]

the amount of heat need is 71060 Joules

Explanation

The equation for the amount of heat needed to increase the temperature of water is as follows:

\begin{gathered} E=mC(T_2-T_1) \\ where \\  \\  \end{gathered}

where E is the amount of heat

C is the specific heat capacity of water having a standard value of 4180 J/kg*K

T is the final ans initial temperature in kelvin

m is the mass

so

Step 1

given

\begin{gathered} mass=m=200\text{ gr=0.2 kg} \\ T_1=10\text{ \degree C} \\ T_2=95\text{ \degree C} \\ C=4180\text{ J/kh*K} \end{gathered}

a) convert the temperature into kelvin

\begin{gathered} 10\text{ \degree C=\lparen10+273\rparen K=283 K} \\ 95\text{ \degree C=\lparen95+273 \rparen K=368 K} \end{gathered}

now, replace in the formula

\begin{gathered} E=mC(T_{2}-T_{1}) \\ E=0.2\text{ kg*4180L/kg*K*\lparen368K-283 k\rparen} \\ E=71060\text{ J} \end{gathered}

therefore, the amount of heat need is 71060 Joules

I hope this helps you

7 0
1 year ago
Read 2 more answers
Given a temperature of 300 Kelvin, what is the approximate temperature in degrees Celsius?
S_A_V [24]
<span>Jun 16, 2012 - Given a temperature of 300 Kelvin, what is the approximate temperature in degrees Celsius? –73°C 27°C 327°C 673°C.</span><span>
</span>
3 0
4 years ago
Read 2 more answers
A machine does 500 j of work in 20 sec. What is the power of this machine?
NNADVOKAT [17]

Explanation:

P=W/t

P=500/20

P=25 W

6 0
3 years ago
What is solubility,malleability and ductility
docker41 [41]
Solubility is the ability to dissolve in liquids like water or organic solvents.
Malleability is the ability to bend and be hammered without breaking.
Ductility is when a material can be stretched into wires.
5 0
3 years ago
At 20°C the vapor pressure of dry ice is 56.5 atm. If 10g of dry ice (solid CO2) is placed in an evacuated 0.25 L chamber at a c
jonny [76]

Answer:

Pressure of the gas is greater than the vapor pressure, therefore all the solid will not sublime.

Explanation:

To solve this problem we use ideal gas equation.

PV =nRT

If Presure of the gas (P) is greater than vapor pressure (56.5 atm), all the solid will not sublime. But If P < 56.5 atm, all of it will sublime.

where;

P is pressure of the gas in atm

V is volume of gas in Litre

T is absolute temperature of the gas in Kelvin

n is number of gas moles

R is ideal gas constant or Boltzmann constant = 0.082057 L atm K⁻¹ mol⁻¹

Given T = 20 °C  = 273 + 20 = 293K

Volume = 0.25L

n = Reacting mas (m)/Molar mass(M)

Molar mass of CO₂ = 12 + (16X2) = 12+32 = 44g/mol

Reacting mass = 10g

n = m/M ⇒ 10/44

n = 0.2273

PV =nRT ⇒ P = nRT/V

P = (0.2273X0.082057 X293)/0.25

P = 21.8596 atm

Therefore, since Pressure of the gas is greater than the vapor pressure, all the solid will not sublime.

5 0
4 years ago
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