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lesya692 [45]
2 years ago
9

Which is an example of the gravitational force?

Physics
2 answers:
Evgesh-ka [11]2 years ago
7 0
1. A basketball was thrown in the air and falls to the ground
Sergeeva-Olga [200]2 years ago
6 0

Answer:

1.a basketball that was thrown in the air falls to the ground

Explanation:

1.a basketball that was thrown in the air falls to the ground

From newton law of universal gravitation, it state that a object of any mass will  have the tendency to come down when throw to the atmosphere.

this is the reason why acceleration due to gravity of any object thrown up are always the same. Acceleration due to gravity on earth is 9.8 m/s2.

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A beam of light strikes a sheet of glass at an angle of 57.0° with the normal in air. You observe that red light makes an angle
Contact [7]
<h2>Answers: </h2>

1) 1.359, 1.403

2) 2.207(10)^{8}m/s,  2.138(10)^{8}m/s    

Explanation:

The described situation is known as Refraction.  

Refraction is a phenomenon in which a wave (the light in this case) bends or changes it direction when passing through a medium with a refractive index different from the other medium.  

In this context, the Refractive index n is a number that describes how fast light propagates through a medium or material, and is defined as the relation between the speed of light in vacuum (c=3(10)^{8}m/s) and the speed of light v in the second medium:

n=\frac{c}{v}   (1)

On the other hand we have the Snell’s Law:  

n_{1}sin(\theta_{1})=n_{2}sin(\theta_{2})   (2)  

Where:  

n_{1} is the first medium refractive index . We are told is the air, hence n_{1}\approx 1

n_{2} is the second medium refractive index  

\theta_{1} is the angle of the incident ray  

\theta_{2} is the angle of the refracted ray  

Knowing this, let's begin with the answers:

<h2><u>1) Indexes of refraction for red and violet light</u></h2><h2 /><h2>1a) Red light</h2>

Using equation (2) according to Snell's Law and \theta_{1}=57.0\º   \theta_{2}=38.1\º:

(1)sin(57.0\º)=n_{2}sin(38.1\º)  

Finding n_{2}:

n_{2}=\frac{sin(57.0\º)}{sin(38.1\º)}  

n_{2}=1.359   (3)>>>Index of Refraction for red light

<h2>1b) Violet light</h2>

Again, using equation (2) according to Snell's Law and \theta_{1}=57.0\º   \theta_{2}=36.7\º:

(1)sin(57.0\º)=n_{2}sin(36.7\º)  

Finding n_{2}:

n_{2}=\frac{sin(57.0\º)}{sin(36.7\º)}  

n_{2}=1.403   (4) >>>Index of Refraction for violet light

<h2><u>2) Speeds of red and violet light</u></h2><h2 /><h2>1a) Red light</h2>

Here we are going to use equation (1):

n_{red}=\frac{c}{v_{red}}

v_{red}=\frac{c}{n_{red}}

Substituting (3) in this equation:

v_{red}=\frac{3(10)^{8}m/s}{1.359}

v_{red}=2.207(10)^{8}m/s >>>>Speed of red light

<h2>1a) Violet light</h2>

Using again equation (1):

n_{violet}=\frac{c}{v_{violet}}

v_{violet}=\frac{c}{n_{violet}}

Substituting (4) in this equation:

v_{violet}=\frac{3(10)^{8}m/s}{1.403}

v_{red}=2.138(10)^{8}m/s >>>>Speed of violet light

3 0
3 years ago
True or False? There is more downward force on a faster car than on a slower car when both
kondor19780726 [428]

Answer:

false

Explanation:

bc the faster car has more inertia (i dont think im correct)

not sure but feels like it

3 0
2 years ago
Where are the most reactive nonmetal elements found on the periodic table?
Sindrei [870]

Answer;

At the top of group 17

Explanation;

Reactivity in chemistry deals with whether something will react with another substance. The reactivity of an element can be predicted based on its location on the periodic table.

The most reactive nonmetal is fluorine. Fluorine is a halogen, which is Group 17 on the periodic table, and the halogens are the most reactive nonmetals. This is because they all have one empty space in their valence electron shells. Of the halogens, fluorine's empty space is closest to the positively charged nucleus. This means it pulls harder on another atom's electrons to fill that empty space.

8 0
2 years ago
Read 2 more answers
Which of the following describes resistance force?
Harman [31]
I am pretty sure that<span> the following which describes resistance force is the fourth option from the scale represented above : </span>D .force applied by the machine to overcome resistance. I choose this due to the  Newton's 3rd law, as the<span> force that shoul be overcome by a machine before it perform its usual work. Do hope you will find it helpful! Regards!</span>
4 0
3 years ago
Read 2 more answers
A cylindrical rod 120 mm long and having a diameter of 15.0 mm is to be deformed using a tensile load of 35,000 N. It must not e
astraxan [27]

Answer: Magnesium Alloy

Explanation:

Cross sectional area A = (pi/4)d sqr

A = pi / 4 x 0.015 sqr

A = 1.76 x 10^-4 m2

Stressed induced in rod S = P/A = 35000/1.76x 10^-4

S= 198.06 M Pa

Reduction in diameter of the titanium alloy = -v (alpha/E) x d

= - 0.33 (( 198.06 X 10^6) / 70 x 10^9 )x 0.015 = - 1.41 x 10^-2 mm

For steel alloy

= - 0.36 (( 198.06 X 10^6) / 150 x 10^9 )x 0.015 = - 1.02 x 10^-2 mm

For magnesium

= 0.27 (( 198.06 X 10^6) / 205 x 10^9 )x 0.015 = 0.391 x 10^-2 mm

The titanium alloy and the steel alloy does not satisfy the second criteria since the reduction in diameter exceeds the allowable limit of 1.2 x 10^2mm
Considering the yield strength of the material, we find the aluminium alloy is not suitable and hence no need to check for the second criteria. By considering the both the given conditions, we find the magnesium alloy is the suitable material.

3 0
2 years ago
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