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riadik2000 [5.3K]
3 years ago
15

What is the momentum of a baseball with a mass of 0.12 kg being thrown

Physics
1 answer:
Savatey [412]3 years ago
5 0

Answer:

5.4kgm/s towards the hitter.

Explanation:

Given parameters:

Mass  = 0.12kg

Velocity  = 45m/s

Unknown:

Momentum of the baseball  = ?

Solution:

To solve this problem, we  must understand that the momentum of a body is the quantity of motion it possesses.

 Momentum  = mass x velocity

 Now insert the parameters and solve;

 Momentum  = 0.12 x 45  = 5.4kgm/s towards the hitter.

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How much current must be applied across a 60 Ω light bulb filament in order for it to consume 55 W of power? Unserious answers w
sergij07 [2.7K]

Answer: current I = 0.96 Ampere

Explanation:

Given that the

Resistance R = 60 Ω 

Power = 55 W

Power is the product of current and voltage. That is

P = IV ...... (1)

But voltage V = IR. From ohms law.

Substitutes V in equation (1) power is now

P = I^2R

Substitute the above parameters into the formula to get current I

55 = 60 × I^2

Make I^2 the subject of formula

I^2 = 55/60

I^2 = 0.92

I = sqr(0.92)

I = 0.957 A

Therefore, 0.96 A current must be applied.

4 0
3 years ago
A small apple weighs 0.8N. How much would an apple that is 4 times as massive weigh?
-BARSIC- [3]

Answer:

W=31.99 N

Explanation:

W= 8 N (N= kg*m/ s^2)

W= m* g

8 N= m * 9.8 m/s^2

m= 0.816 kg

m*4= (0.816)4

= 3.264 kg

W= mg

= (3.264 kg)(9.8 m/s^2)

W=31.99 N

4 0
3 years ago
. If measurements of a gas are 75L and 300 kilopascals and then the gas is measured a second time and found to be 50L, describe
julia-pushkina [17]
By Boyle's law:

P₁V₁ = P₂V₂

300*75 = P<span>₂*50

</span>P<span>₂*50= 300*75
</span>
P<span>₂ = 300*75/50 = 450
</span>
P<span>₂ = 450 kiloPascals.

The pressure has increased as a result of compression of gas.

Boyle's Law supports this observation.</span>
3 0
3 years ago
Read 2 more answers
A body with mass 4 kg moves with a velocity of 108km/h <br> Calculate it kinetic<br> energy
Fed [463]

Explanation:

The answer is in the pic above

4 0
3 years ago
A cyclist acceleration from 0m/s to 8m/s in 3second. what is his acceleration?​
umka2103 [35]

Answer:

2.66 m/s² .

Explanation:

Initial velocity , u = 0 m/s

Final Velocity , v = 8 m/s

Time Taken , t = 3 s

So , Acceleration = (v-u)/t = (8 m/s - 0 m/s) /3 sec . = 8/3 m/s² = 2.66 m/s²

4 0
3 years ago
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