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pshichka [43]
3 years ago
15

You are 15.0m from the source of a sound. At that distance, you hear it at a sound level of 20.0dB. How close must you move to t

he sound to increase the sound level to 60dB?
I think its 45.0cm?

15.0cm
45.0cm
55.0cm
60.0cm
85.0cm
Physics
2 answers:
Andrej [43]3 years ago
5 0
The answer is 45.0cm
USPshnik [31]3 years ago
4 0

Answer:

Explanation:

its 85 cm because it just is in meters it would be .8m  which would be decent distance to hear it

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A 25.0 kg pickle is accelerated from rest through a distance of 6.0m in 4.0s across a level floor . If the friction force betwee
SIZIF [17.4K]
Add the KE increase and the work done against friction.

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Arcsin 0.9331 in degrees​
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Answer:

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The provided question's answer is "Schwarzschild radius".

The conversion factor between mass and energy is the speed of light squared.

GM/r stands for gravitational potential energy, also known as energy per unit mass.

GM/rc² then has "mass per unit mass" units. In other words, as mass/mass splits out in a dimensional analysis, "dimensionless per unit."

The derivation yields a formula for time or space coordinate ratios requiring sqrt(1 - 2GM/rc²). This number becomes 0 when r=2GM/c2, or the formula becomes infinite if in the denominator. However, there is no justification for using c² as a conversion factor there. Consider the initial expression sqrt(1 - 2GM/rc²).

Assume that m is used as the test particle's mass instead of 1. Then you have sqrt(m - 2GMm/rc² and mass units. This expression denotes that the rest energy of the test mass m you introduced into the gravitational field is "gone" at that radius.

The 2 would be absent if the gravitational field were Newtonian. However, at the event horizon, Einstein gravity is slightly stronger than Newton gravity, resulting in the factor 2 in qualitative terms.

So, the given equation is of Schwarzschild radius.

Learn more about Schwarzschild radius here:

brainly.com/question/12647190

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