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2 years ago

Compare superconductors and semiconductors with conductors and insulators

2 answers:

5 0

Well a superconductor is a metal that acts strangely when cooled down to a certain temperature and a semiconductor and on the flip side a semiconductor<span>, is a material that has a conductivity somewhere between that of a conductor and an insulator. that is pretty much what i know i hope this helps</span>

grandymaker [24]2 years ago

4 0

The gap generally refers to the energy difference between the top valence band in insulators and semiconductors. The band gap is a major factor in determining the electrical conductivity of a solid. ... Semiconductors Conductors Materials that conduct electricity are known as conductors.

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When heat is converted into another form of energy, the total amount of energy is constant. Which law best illustrates this stat

deff fn [24]

The law of conservation of energy states that in a closed or isolated system, the amount of energy remains constant because energy can neither be created or destroyed. It can only be transferred from one form into another. This applies to all forms of energy.

8 0

3 years ago

this is a 3 part questionOn vacation, your 1400-kg car pulls a 560-kg trailer away from a stoplight with an acceleration of 1.85

mamaluj [8]

ANSWER:

(a) 1036 N

(b) -1036 N

STEP-BY-STEP EXPLANATION:

Given:

Mc = 1400 kg

Mt = 560 kg

a = 1.85 m/s^2

(a)

Force by car on trailer:

$\begin{gathered} F_c=m\cdot a \\ F_c=560\cdot1.85 \\ F_c=1036\text{ N} \end{gathered}$

(b)

$\begin{gathered} F_t=-F_c \\ F_t=-1036\text{ N} \end{gathered}$

(c)

$\begin{gathered} F_n=1400\cdot1.85 \\ F_n=2590\text{ N} \end{gathered}$

3 0

10 months ago

Suppose you want to make a nested function call (i.e. a call to a function from inside of another function) using a jal rather t

WARRIOR [948]

Answer:

As we need to use a nested loop in our function,hence push $ra

pop $ra

jal nested_function_label

nop is the correct option.

8 0

3 years ago

At a point between the earth and the moon, the magnitude of the force exerted on an object by the earth's gravity equals the mag

S_A_V [24]

1.62 m/s is the correct answer to the problem

8 0

3 years ago

You have a radioactive sample with a half-life of 1 hour. At t = 1 hour, a Geiger counter measures its radiation at 40 counts/mi

Mama L [17]

Answer:

Explanation:

Given that, .

The half-life of a radioactive element is

t½ = 1 hr.

At the first hour, the radioactive element has 40 counts/minute

After 4 hours it has 5 counts/minute

So,

We want to filled the table.

0 hours, I.e at the start

40 counts/mins × 2 = 80 counts / mis

First half-life (first hour) is

40 counts/mins

Second half-life (second hour)

40 counts/mins × ½ = 20 counts/mins

Third half-life (third hour)

40 counts/mins × ¼ = 10 counts / mins

Fourth half life (fourth hour)

40 counts/mins × ⅛ = 5 counts / mins

So, the table is

Time........................Geiger Counter Rate

0 hours.................... 80 counts / minutes

1 hour........................ 40 counts / minutes

2 hours..................... 20 counts / minutes

3 hours..................... 10counts / minutes

4 hours...................... 5 counts / minute

6 0

3 years ago