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natima [27]
2 years ago
14

What information could you gather about a star if its light curve had multiple

Physics
2 answers:
yanalaym [24]2 years ago
7 0

The information that could be gathered about a star whose light curve has multiple symmetrical depths is ; The shape and surface variegation of the star

The light curves of a KBO ( moons and stars ) are measured as a rate of the brightness of a star in relation to time. therefore the study of the light curve having multiple symmetrical depths ( depth of brightness ) will give an information about the shape/size and the surface variegation of the star

Hence we can conclude that The information that could be gathered about a star whose light curve has multiple symmetrical depths is ; The shape and surface variegation of the star

Learn more : brainly.com/question/19573734

Vlad [161]2 years ago
7 0

Answer:

When studying a light curve we can use that information to figure out what kind of object it is.  By measuring the dip in brightness and knowing the size of the star, scientists can determine the size or radius of the planet.

Explanation:

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A hockey puck is sliding at a constant rate of 2m/s on a frictionless surface. How fast will the puck be moving after 10 sec
AnnyKZ [126]
2m/s because the hockey puck is traveling at a constant speed ( acceleration is 0 ). Unless something acts on the hockey puck it will travel 2 m/s forever.
5 0
2 years ago
The height of a projectile t seconds after it is launched straight up in the air is given by f (t )equals negative 16 t squared
velikii [3]

Answer:

\displaystyle a(5)=-32

Explanation:

<u>Instant Acceleration</u>

The kinetic magnitudes are usually related as scalar or vector equations. By doing so, we are assuming the acceleration is constant over time. But when the acceleration is variable, the relations are in the form of calculus equations, specifically using derivatives and/or integrals.

Let f(t) be the distance traveled by an object as a function of the time t. The instant speed v(t) is defined as:

\displaystyle v(t)=\frac{df}{dt}

And the acceleration is

\displaystyle a(t)=\frac{dv}{dt}

Or equivalently

\displaystyle a(t)=\frac{d^2f}{d^2t}

The given height of a projectile is

f(t)=-16t^2 +238t+3

Let's compute the speed

\displaystyle v(t)=-32t+238

And the acceleration

\displaystyle a(t)=-32

It's a constant value regardless of the time t, thus

\boxed{\displaystyle a(5)=-32}

3 0
3 years ago
Protons are the smallest particle of an element that retains the original Characteristics of the element. True or False
dlinn [17]

Answer:

False; that’s an atom

Explanation:

5 0
3 years ago
Read 2 more answers
Anyone know how to do this ?
soldi70 [24.7K]
Not really but I need points lol
3 0
3 years ago
Read 2 more answers
The velocity of a 0.25kg model rocket changes from 15m/s [up] to 40m/s [up] in
pochemuha

Since g is constant,  the force the escaping gas exerts on the rocket will be 10.4 N

<h3>What is Escape Velocity ?</h3>

This is the minimum velocity required for an object to just escape the gravitational influence of an astronomical body.

Given that the velocity of a 0.25kg model rocket changes from 15m/s [up] to 40m/s [up] in 0.60s. The gravitational field intensity is 9.8N/kg.

To calculate the force the escaping gas exerts of the rocket, let first highlight all the given parameters

  • Mass (m) of the rocket 0.25 Kg
  • Initial velocity u = 15 m/s
  • Final Velocity v = 40 m/s
  • Time t = 0.6s
  • Gravitational field intensity g = 9.8N/kg

The force the gas exerts of the rocket = The force on the rocket

The rate change in momentum of the rocket = force applied

F = ma

F = m(v - u)/t

F = 0.25 x (40 - 15)/0.6

F = 0.25 x 41.667

F = 10.42 N

Since g is constant,  the force the escaping gas exerts on the rocket is therefore 10.4 N approximately.

Learn more about Escape Velocity here: brainly.com/question/13726115

#SPJ1

7 0
1 year ago
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