Answer:
18.89cm
Explanation:
As we know that the person is standing 5m in front of the camera

The focal length of the lens =50cm
f=50 cm
By Lens formula we have:

By the formula of magnification

The height of the image formed is 18.89cm.
Answer:
~~Now, you have left your question very open ended and didn't ask for any particular kind of answer so I'll do my best to get what you're looking for.~~
A physical change in a substance doesn't change what the substance is. It can possibly melt or freeze an object. I mean heat makes things expand while cooling makes them retract.... In chemical change where there is a chemical reaction, a new substance is formed and energy is either given off or absorbed.
Answer:
to make calculation more easy to get
Explanation:
if you are using chart or calculate Thermodynamic problems you will not never solve this problem with out using data table for thermodynamic
Answer:
A. 4.47 m/s
Explanation:
As the ball oscillates, it mechanical energy, aka the total kinetic and elastics energy stays the same. For the ball to be at maximum speed, its elastic energy i 0 and vice versa. When the ball is at rest, its kinetic energy is 0 and its elastic energy is at maximum at 50 cm, or 0.5 m
1500 g = 1.5 kg





