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miv72 [106K]
3 years ago
12

What is the second most abundant element in the universe? a. h b. c c. fe d. he

Physics
1 answer:
Andru [333]3 years ago
7 0
D I think I'm not sure!?.
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If the distance between the two objects is reduced in half, what will be the changed force of attraction between them?
NNADVOKAT [17]
Will reduce 4 times.

F =  G \frac{m1* m2}{ d^{2} }
So called LUG (Law of Universal gravitation).
8 0
3 years ago
You get pulled over for running a red light. You explain to the police officer that the light appeared green to you due to the D
Ludmilka [50]

Answer:

$ 3085713685.71

Explanation:

\lambda_0 = Actual wavelength = 700 nm

\lambda = Changed wavelength = 500 nm

Let the wavelength of red color be 700 nm and green be 500 nm

Change in wavelength is

\Delta \lambda=700-500\\\Rightarrow \theta\lambda=200\ nm

We have the relation

\dfrac{\Delta\lambda}{\lambda_0}=\dfrac{v}{c}\\\Rightarrow v=\dfrac{\Delta\lambda}{\lambda_0}c\\\Rightarrow v=\dfrac{200}{700}\times 3\times 10^8\\\Rightarrow v=85714285.7143\ m/s

The speed of the vehicle is 85714285.7143 m/s

\dfrac{85714285.7143\times 3600}{1000}=308571428.571\ km/h

By how much was the car speeding

308571428.571-60=308571368.571\ km/h

The number of 10 km/h in the above speed

308571368.571\times\dfrac{1}{10}=30857136.8571

Cost of the ticket

30857136.8571\times 100=\$ 3085713685.71

The cost of the ticket is $ 3085713685.71

8 0
3 years ago
Read 2 more answers
An object has an initial velocity of 15 m/s. How long must it accelerate at a constant rate of 3. 0 m/s² before its final veloci
Lera25 [3.4K]

Answer: 5 sec

Explanation:

30 = 15 + (3*t)

so, t=(30-15)÷3

       = 5 sec

4 0
2 years ago
Visible light occupies the majority of the electromagnetic spectrum? Ture or false
Novosadov [1.4K]
From what i can tell its false
5 0
3 years ago
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Why gravitational force at the center og earth is zero
KengaRu [80]
F = G Mm/r²
mg = G Mm/r²
g = GM/r²
At centre of earth, r=0
g = GM/0
g =0
8 0
3 years ago
Read 2 more answers
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