What is the second most abundant element in the universe? a. h b. c c. fe d. he
1 answer:
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Answer:
2.7067 eV
Explanation:
h = Planck's constant =
c = Speed of light =
= Threshold wavelength = 459 nm
Work function is given by
Converting to eV
The work function W0 of this metal is 2.7067 eV
Answer:
A) B = 5.4 10⁻⁵ T, B) the positive side of the bar is to the West
Explanation:
A) For this exercise we must use the expression of Faraday's law for a moving body
fem =
fem = - d (B l y) / dt = - B lv
B =
we calculate
B = - 7.9 10⁻⁴ /(0.73 20)
B = 5.4 10⁻⁵ T
B) to determine which side of the bar is positive, we must use the right hand rule
the thumb points in the direction of the rod movement to the south, the magnetic field points in the horizontal direction and the rod is in the east-west direction.
Therefore the force points in the direction perpendicular to the velocity and the magnetic field is in the east direction; therefore the positive side of the bar is to the West