All categories

2 years ago

16^5/4•16^1/4/(16^1/2)^2

Mathematics

1 answer:

Kazeer [188]2 years ago

8 0

Answer:

The simplified expression is 16^-1/6

Step-by-step explanation:.

16^5/4•16^1 /4/ (16^1/2)^2

The dot means multiplication. The expression is rewritten as

16^5/4 × 16^1/4 / (16^1/2)^2

Recall the following rules of indices

1) y^a × y^b = y^(a+b)

2) (y^a)^b = y^ab

y^b/ y^a = y^(b-a)

Applying these rules of indices

16^5/4 × 16^1/4= 16^((5/4×1/4) = 16^((5/16)

(16^1/2)^2= 16^ 1/2×2 = 16^1 = 16

Therefore

16^5/4 × 16^1/4 / (16^1/2)^2

= 16^(5/16) /16

=16^(5/6) × 16^-1

= 16^ (5/6)-1

= 16^-1/6)

,The simplified expression is 16^-1/6

You might be interested in

Whats the slope for this question?

Nastasia [14]

Answer:

Slope: 1

Step-by-step explanation:

A variable is always worth 1 if there is no number in front of it. In this case there is no number, so just draw in a one.

6 0

2 years ago

Read 2 more answers

Find the Value of |25|

denpristay [2]

Answer:

Step-by-step explanation:

an absaloute value means that every number inside of that would be a positive number.

4 0

2 years ago

Read 2 more answers

Pre image ABCD was dilated to be image A’B’C’D, where the center of dilation is the origin. What scale factor was used in the di

ArbitrLikvidat [17]

Answer:

The scale factor is 0.25

Step-by-step explanation:

we know that

The dilation is a non-rigid transformation that produce similar figures

If two figures are similar, then the ratio of its corresponding sides is proportional and this ratio is called the scale factor

In this problem

ABCD and A'B'C'D' are similar

therefore

$\frac{A'B'}{AB}=\frac{B'C'}{BC}=\frac{C'D'}{CD}=\frac{A'D'}{AD}$

Find the scale factor

Looking at the graph

we have

$A'B'=1\ unit\\AB=4\ units$

Let

z ---> the scale factor

$z=\frac{A'B'}{AB}$

substitute the values

$z=\frac{1'}{4}=0.25$

8 0

2 years ago

Plz helppppppppppppppp

lorasvet [3.4K]

Answer:

I think it's the third one sry if I'm wrong

5 0

2 years ago

Read 2 more answers

According to the U.S. Census Bureau, the mean of the commute time to work for a resident of Boston, Massachusetts, is 27.3 minut

Bond [772]

Answer:

By the Chebyshev Theorem, at least 75% of commuters in Boston has a commute time within 2 standard deviations of the mean

Step-by-step explanation:

Chebyshev Theorem

The Chebyshev Theorem can also be applied to non-normal distribution. It states that:

At least 75% of the measures are within 2 standard deviations of the mean.

At least 89% of the measures are within 3 standard deviations of the mean.

An in general terms, the percentage of measures within k standard deviations of the mean is given by $100(1 - \frac{1}{k^{2}})$ .

What minimum percentage of commuters in Boston has a commute time within 2 standard deviations of the mean

By the Chebyshev Theorem, at least 75% of commuters in Boston has a commute time within 2 standard deviations of the mean

7 0

2 years ago