Question

Can someone help me with these? No clue how to do it or what the answer is​

Answer 1

Answer:

see explanation

Step-by-step explanation:

Given

f(x) = $x^{4}$ + 3x³ - 4x²

To find the zeros equate f(x) to zero, that is

$x^{4}$ + 3x³ - 4x² = 0 ← factor out x² from each term

x²(x² + 3x - 4) = 0 ← factor the quadratic

x²(x + 4)(x - 1) = 0 ← in standard form

Equate each factor to zero and solve for x

x² = 0 ⇒ x = 0 with multiplicity 2

x + 4 = 0 ⇒ x = - 4

x - 1 = 0 ⇒ x = 1

zeros are x = - 4, x = 0, x = 1