Question

A child in an inner tube is bobbing up and down in the ocean and notices that after a wave crest passes, four more crests pass in a time of 38.4 s and the distance between the crests is 32 m. If possible, determine the following properties for the wave. (If not possible, enter IMPOSSIBLE.)(a) Period (s)(b) Frequency (Hz)(c) Wavelength (m)(d) Speed ( m/s)(e) Amplitude (m)

Answer 1

Answer:

Explanation:

Given:

Four more crests pass in a time of 38.4 s and the distance between the crests is 32 m.

We have to determine five terms.

Lets start with one-one basis.

a.  

Period = Time taken by a wave to pass though.

⇒  $P = \frac{Total\ time}{No.\ of\ waves}$

⇒ $P = \frac{38.4}{4}$

⇒ $P=9.6 s$

b.  

Frequency = Reciprocal of time period in Hertz.

⇒ $f=\frac{1}{T}$

⇒$f=\frac{1}{9.6}$

⇒ $f=0.104 Hertz$

c)

Wavelength = Distance between two consecutive trough and crest.

⇒ $\lambda = 32 m$

d.

Speed (v) = Product of frequency and wavelength.

⇒ $v=f\times \lambda$

⇒ $v=0.104\times 32$

⇒$v = 3.33 ms^-1$

e)

Amplitude = The maximum displacement or half the distance from crest to trough.

⇒ Here it can't be determined.

⇒ Impossible.