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gogolik [260]
3 years ago
11

How far can a person run in 0.25hr if he or she runs at a average speed of 16km/he?

Physics
1 answer:
Gala2k [10]3 years ago
3 0

Answer:

4km

Explanation:

d = st

d=0.25*16

d=4km

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2. A race car starts at 400 m/s and then stops in 20 seconds. Calculate acceleration. Acceleration=final velocity - initial velo
Nostrana [21]
It is -20m/s2
400-0
————- = -20
20
5 0
3 years ago
Can a goalkeeper at her/ his goal kick a soccer ball into the opponent’s goal without the ball touching the ground? The distance
PSYCHO15rus [73]

Answer:

No she cannot.

Explanation:

Let v_h be the horizontal component of the ball velocity when it's kicked, assume no air resistance, this is a constant. Also let v_v be the vertical component of the ball velocity, which is affected by gravity after it's kicked.

The time it takes to travel 95m accross the field is

t = 95 / v_h or v_h = 95/t

t is also the time it takes to travel up, and the fall down to the ground, which ultimately stops the motion. So the vertical displacement after time t is 0

s = v_vt + gt^2/2= 0

where g = -9.8m/s2 in the opposite direction with v_v

v_vt - 4.9t^2 = 0

v_vt = 4.9t^2

v_v = 4.9t

Since the total velocity that the goal keeper can give the ball is 30m/s

v = v_v^2 + v_h^2 = 30^2 = 900

(4.9t)^2 + \left(\frac{95}{t})^2 = 900

24.01t^2 + \frac{9025}{t^2} = 900

Let substitute x = t^2 > 0

24.01 x + \frac{9025}{x} = 900

We can multiply both sides by x

24.01 x^2 + 9025 = 900x

24.01x^2 - 900x + 9025 = 0

t= \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}

t= \frac{900\pm \sqrt{(-900)^2 - 4*(24.01)*(9025)}}{2*(24.01)}

As (-900)^2 - 4*24.01*9025 = -56761 < 0

The solution for this quadratic equation is indefinite

So it's not possible for the goal keeper to do this.

6 0
3 years ago
Your fitness tracker tells you that you have delivered 124 kJ of work during your workout. The tracker also shows that you have
REY [17]

To solve this problem, we must basically count the total energy lost converting all the values given in the international system.

The energy loss is given by both 124KJ and 124food heats.

Since the energy conversion we know that 1 food calories is equal to 4,184J. So:

124 calories (\frac{4.184J}{1 calories}) = 518.816J = 0.518816kJ

Therefore the total energy lost will be

E_{lost} = 124 KJ + 0.518816 KJ

E_{lost} = 124.518KJ

Therefore the total energy lost to the surroindings in form of heat is 124.518kJ

3 0
3 years ago
Which particle will be deflected toward the positive plate as it enters the electric field
Juli2301 [7.4K]

Answer:

Electrons are negatively charged and are deflected on a curving path towards the positive plate. Neutrons have no charge, and continue on in a straight line.

3 0
3 years ago
Read 2 more answers
If a paper is blue what color of light bounces off the paper
SashulF [63]
Blue bounces off the paper
7 0
3 years ago
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