Question

Por un solenoide de 6500 espiras y 25 cm de longitud circula una corriente de 0,6 amperios. ¿Cuál es el valor del campo magnético en su interior?

Answer 1

Answer:

Magnetic field, B = 0.0196 T

Explanation:

A current of 0.6 amps flows through a solenoid 6500 turns and 25 cm long. What is the value of the magnetic field inside it?

We have,

Current, I = 0.6 A

Number of turns in the solenoid, N = 6500

Length of solenoid, l = 25 cm = 0.25 m

The magnetic field inside the solenoid is given by :

$B=\mu_o\dfrac{N}{l}I\\\\B=\dfrac{4\pi \times 10^{-7}\times 6500\times 0.6}{0.25}\\\\B=0.0196\ T$

So, the value of the magnetic field inside the solenoid is 0.0196 T.