The options are missing from the question.
Below are the options.
A) 192.168.15.0
B) 192.168.15.16
C) 192.168.15.32
D) 192.168.15.64
Answer: The correct option to the question is option D
192.168.15.64
Explanation:
The Network is: 192.168.15.64/26 11000000.10101000.00001111.01000000
Then the Broadcast is: 192.168.15.127 11000000.10101000.00001111.01111111
We see the HostMin as: 192.168.15.65 11000000.10101000.00001111.01000001
And the HostMax as: 192.168.15.126 11000000.10101000.00001111.01111110
Answer:
Following are the code to this question:
please find the attached file.
Explanation:
In this code, four class "novels, magazines, technical journals, and textbooks", is defined, in which it holds their respective default constructor and the get and set method to hold the string and integer value, and in the book class the main method is defined, that creates its object and a switch to for search value and print its value.
<u>Answer:</u>
The correct answer option is D. set the switch to the highest range and then move it to a range that gives the most accurate reading.
<u>Explanation:</u>
When measuring an unknown voltage with an analog VOM, one should set the meter to the highest range and then move it to a range that gives the most accurate reading.
The reason being that the analog meters indicate the measurement of voltage by moving a needle across a physical card by printing numbers on it.
So in case the voltage is nearly 100 times the full range to which the meter is set, then its needle will try move to a position which will be 100 times the highest number on the meter.