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Thepotemich [5.8K]
3 years ago
7

Thirty four and nine ten thousandths

Mathematics
1 answer:
dybincka [34]3 years ago
7 0
34.100 efefref evf dewdcec
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13. A certain town with a population of 100,000 has 3 newspapers: I, II, and III. The proportions of townspeople who read these
Lina20 [59]

Answer:

24,000 people read only one newspaper

12,000 people read at least two newspapers

11,000 people read at least one morning paper plus an evening paper.

64,000 people do not read any newspapers.

10,000 people read only one morning paper and one evening paper.

Step-by-step explanation:

The problem states that:

- 10 percent of the population reads the newspaper I = 10,000

- 8 percent of the population reads the newspaper I and II = 8,000

- 1 percent of the population reads the newspaper I and II an III = 1,000

- 30 percent of the population reads the newspaper III = 30,000

- 2 percent of the population reads the newspaper I and III = 2,000

- 5 percent of the population reads the newspaper III = 5,000

- 4 percent of the population reads the newspaper II and III = 4,000.

Then we have to build the Venn diagram for this: I am going to call

- A the people that read the newspaper I

- B the people that read the newspaper II

- C the people that read the newspaper III

We start this from the people that read each newspaper

A \cap B \cap C = 1,000 - 1,000 people read each newspaper

The people that read only I and II are the number of people that read I and II minus the number of people that read I, II and III. So:

A \cap B = 8,000 - A \cap B \cap C = 8,000 - 1,000 = 7,000

It applies for I and III

A \cap C = 2,000 - A \cap B \cap C = 2,000 - 1,000 = 1,000

And for II and III

B \cap C = 4,000 - A \cap B \cap C = 4,000 - 1,000 = 3,000

The problem states that 10,000 people read the newspaper I, so:

A + (A \cap B) + (A \cap C) + (A \cap B \cap C) = 10000 where A is the number of people that read only the newspaper I. So:

A + 7,000 + 1,000 + 1,000 = 10,000

A + 9,000 = 10,000

A = 1,000

30,000 read the newspaper II, so:

B + (A \cap B) + (B \cap C) + (A \cap B \cap C) = 30,000

B + 7,000 + 3,000 + 1,000 = 30,000

B + 11,000 = 30,000

B = 19,000

5,000 read the newspaper III, so:

C +  (A \cap C) + (B \cap C) + (A \cap B \cap C) = 5,000

C + 1,000 + 1,000 + 1,000 = 5,000

C = 2,000

The answers:

a) Find the number of people who read only one newspaper

A + B + C = 1,000 + 21,000 + 2,000 = 24,000

24,000 people read only one newspaper

b) How many people read at least two newspapers

(A \cap B) +  (A \cap C) + (B \cap C) + (A \cap B \cap C) = 7,000 + 1,000 + 3,000 + 1,000 = 12,000

12,000 people read at least two newspapers

If I and III are morning papers and II is an evening paper, how many people read at least one morning paper plus an evening paper?

(A \cap B) + (B \cap C) + (A \cap B \cap C) = 7,000 + 3,000 + 1,000 = 11,000

11,000 people read at least one morning paper plus an evening paper.

How many people do not read any newspapers?

There is 100,000 people in the town.

So, the number of people that does not read any newspaper is:

100,000 - (A + B + C + (A \cap B) +  (A \cap C) + (B \cap C) + (A \cap B \cap C)) = 100,000 - 36,000 = 64,000

64,000 people do not read any newspapers.

How many people read only one morning paper and one evening paper?

(A \cap B) + (B \cap C) = 7,000 + 3,000 = 10,000

10,000 people read only one morning paper and one evening paper.

3 0
3 years ago
Find the orthocenter for the triangle described by each set of vertices
swat32

Answer:

The answer to your question is:  O(10/3, -17/3)

Step-by-step explanation:

See the picture

6 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20-%20%20%5Cfrac%7B4%7D%7B5%7D%20t%20%2B%20%20%5Cfrac%7B2%7D%7B5%7D%20%3D%20%20%5Cfrac%7B2%7D
algol [13]

-  \frac{4}{5} t +  \frac{2}{5}  =  \frac{2}{3}

Multiply both sides by 15
- 12t + 6 = 10
Move constant to the right
- 12t = 10 - 6
Subtract the numbers
- 12t = 4
Divide both sides by - 12
t =  -  \frac{1}{3}
I hope that helped!!

5 0
3 years ago
Which relation is a function ?​
musickatia [10]

Answer:

A relation from a set X to a set Y is called a function if each element of X is related to exactly one element in Y. That is, given an element x in X, there is only one element in Y that x is related to. For example, consider the following sets X and Y.

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3 years ago
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What is the slope of the line?<br> x+ 3y = 10
sineoko [7]

Answer:

-1/3

Step-by-step explanation:

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