Answer:
public class MovieRental
{
public static void main(String[] args)
{
Scanner in = new Scanner(System.in);
System.out.print("Enter the number of movie rentals: ");
int movieRentals = in.nextInt();
System.out.print("Enter the number of members referred to the video club: ");
int memberReferral = in.nextInt();
in.close();
double discountVal = Math.min(movieRentals + memberReferral, 75);
System.out.println("The discount is equal to: " + discountVal);
}
}
Step-by-step explanation:
According to the cosine rule :
a = b² + c² - 2bc × cosA
a = 7² + 10² - 2 × 7 × 10 × cos40⁰
a = 49 + 100 - 106.4
a = 149 - 106.4
a = 43.4
Answer:
∠KNC and ∠KMC are right angles
∠MCN = 25°
Step-by-step explanation:
if KM and KN are tangent lines, then they are perpendicular to the radius going through the tangent point, so therefore right angles are:
1. ∠KNC
2. ∠KMC
the outside angle of a circle is equivalent to half the measure of the intercepted arc, so
if ∠MKN = 50°, then ∠MCN = 25°
The answer is x^2 - 4x +4. What I did was set it up as a ratio, FOILing out the two denominators on the left to get (x-5)?/(x^2 - 7x + 10) = (x+1)/1. Next I cross-multiplied to get (x-5)? = (x+1)(x^2 - 7x + 10). Next I FOILed out the right side to get (x-5)? = x^3 - 9x^2 + 24x - 20. Now I have an equation just like 3x=9, for example, where I divide both sides by 3 to find x. Instead, since we have polynomials, we have to use long division. Divide the x^3 term by x-5 and you'll get it.