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3 years ago

Please help me with this and thank you

Mathematics

1 answer:

spin [16.1K]3 years ago

7 0

6/(1/3)= 18

6(3)=18

the answer would be c

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If you have 9/10 of a pound of granola how many 1/5 pound bags can you fill ?

Lostsunrise [7]

Answer:

Step-by-step explanation:

1/5 is the same as 2/10. How many 2's can you put in 9? You can put 4.5 2's in a 9. However, filling half a bag does not fill the entire bag, so the answer would be 4. You can fill 4 full 1/5 pound bags with 9/10 pounds of granola.

3 0

3 years ago

Calculate, to four decimal places, the first ten terms of the sequence. an = 1 +(−4/9)^n

Lemur [1.5K]

The first ten terms of the sequence $a_n=1 + (-\frac{4}{9} )^n$ is<em> 0.5556, 1.1975, 0.9122, 1.039, 0.9827, 1.0077, 0.9966, 1.0015, 0.9993 and 1.0003</em>

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more variables and numbers.

Given that:

$a_n=1 + (-\frac{4}{9} )^n\\\\When\ n=1:a_1=1 + (-\frac{4}{9} )^1=0.5556\\\\When\ n=2:a_2=1 + (-\frac{4}{9} )^2=1.1975\\\\When\ n=3:a_3=1 + (-\frac{4}{9} )^3=0.9122\\\\When\ n=4:a_4=1 + (-\frac{4}{9} )^4=1.039\\\\When\ n=5:a_5=1 + (-\frac{4}{9} )^5=0.9827\\\\When\ n=6:a_6=1 + (-\frac{4}{9} )^6=1.0077\\\\When\ n=7:a_7=1 + (-\frac{4}{9} )^7=0.9966\\\\When\ n=8:a_8=1 + (-\frac{4}{9} )^8=1.0015\\\\When\ n=9:a_9=1 + (-\frac{4}{9} )^9=0.9993\\\\$

$When\ n=10:a_{10}=1 + (-\frac{4}{9} )^{10}=1.0003\\$

The first ten terms of the sequence $a_n=1 + (-\frac{4}{9} )^n$ is<em> 0.5556, 1.1975, 0.9122, 1.039, 0.9827, 1.0077, 0.9966, 1.0015, 0.9993 and 1.0003</em>

Find out more on equation at: brainly.com/question/2972832

#SPJ1

3 0

2 years ago

Mrs. Barnes washed 2 7 of her laundry. Her son washed 1 4 of it. Who washed most of the laundry? How much of the laundry still n

wlad13 [49]

Answer:

Mrs. Barnes washed more.

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Show all steps!!!

Lunna [17]

$-\frac{1}{3}\left|1\cdot \left(\frac{1}{2}\right)^2\right|-\frac{2}{3}-2^3-\frac{2}{3}\left|-\frac{1}{2}\right|^3$
$\frac{1}{3}\left|1\cdot \left(\frac{1}{2}\right)^2\right|=\frac{1}{12}$
$\frac{2}{3}\left|-\frac{1}{2}\right|^3=\frac{1}{12}$
$=-\frac{1}{12}-\frac{2}{3}-2^3-\frac{1}{12}$
$=-\frac{53}{6}$

4 0

3 years ago

Please very urgent!!!

OleMash [197]

Answer:

216

Step-by-step explanation:

hindi pa sure pero yan

7 0

3 years ago