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Drupady [299]
3 years ago
8

Write formulas for each of the following compounds:

Chemistry
1 answer:
zloy xaker [14]3 years ago
6 0
A. Phosphorus (III) iodide:PI3
<span>b. Sulfur (II) chloride :SCl2</span>
<span>c. Carbon (IV) sulfide :CS2</span>
<span>d. Nitrgoen (V) oxide:N2O5
hope it helps

</span>
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How many moles are in 55.0 g calcium nitrate?
Alex17521 [72]

Answer: 0.335 mols Ca(NO3)2

Explanation: To go from grams to mols you divide grams by the molar mass of the substance so, 55/164.088 = 0.335

5 0
3 years ago
Karen is 17 years ild and has a BMI that indicates appropriate weight.She loves to eat all kinds of food. which strategy will be
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She needs to set boundaries

Explanation:

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4 0
3 years ago
How much Sr(OH)2 • 8 H2O (M = 265.76) is needed to prepare 250.0 ML of solution in which [OH]= 0.100M?
SVEN [57.7K]
Use the formula 
first step: 
Use the formula 
molarity= mole/liter
change ml to l
plug in data
 to get .1=mole/.25 or .1M*.25liter
which =.025 moles
then divide .025 moles by two because there are two OH in Sr(OH)2 
then multiply that by 265.76 (the molar mass of water) 
.0125*265.76
which is 3.32grams this is your answer 




6 0
3 years ago
Read 2 more answers
How is the potential (voltage) of a redox reaction determined using the reduction
LuckyWell [14K]

Answer:

caused by the ability of electrons to flow from one half cell too the other

Explanation:

How is the potential voltage of a redox reaction?

The potential difference is caused by the ability of electrons to flow from one half cell to the other. Electrons are able to move between electrodes because the chemical reaction is a redox reaction. A redox reaction occurs when a certain substance is oxidized, while another is reduced.

6 0
2 years ago
10) How many grams are there in 1.00 x 10^24 molecules of BC13?
lana66690 [7]

194.5 g of BCl₃ is present in 1 × 10²⁴ molecules of BCl₃.

Explanation:

In order to convert the given number of molecules of BCl₃ to grams, first we have to convert the molecules to moles.

It is known that 1 moles of any element has 6.022×10²³ molecules.

Then 1 molecule will have \frac{1}{6.022*10^{23} } moles.

So 1*10^{24} molecules = \frac{1*10^{24} }{6.022*10^{23} } =1.66 moles

Thus, 1.66 moles are included in BCl₃.

Then in order to convert it from moles to grams, we have to multiply it with the molecular mass of the compound.

As it is known as 1 mole contains molecular mass of the compound.

As the molecular mass of BCl₃ will be

Molecular mass of BCl_{3}= Mass of Boron + (3*Mass of chlorine)

Mass of boron is 10.811 g and the mass of chlorine is 35.453 g.

Molar mass of BCl₃ = 10.811+(3×35.453)=117.17 g.

grams of BCl_{3}=Molar mass of BCl_{3}*Number of moles

grams of BCl_{3}=117.17*1.66=194.5 g

So, 194.5 g of BCl₃ is present in 1 × 10²⁴ molecules of BCl₃.

3 0
3 years ago
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