Answer:
1.5 atm is the pressure of dinitrogen tetroxide after equilibrium is reached the second time.
Explanation:
initially
4.9 atm 0
At equilbrium:
(4.9-2p) p
Pressure of nitrogen dioxide gas at equilibrium = 2.7 atm
So, (4.9-2p) = 2.7 atm
p = 1.1 atm
The value of equilibrium constant :
After addition of 1.2 atm of nitrogen dioxide gas more to the flask,will the reestablish an equilibrium in flask.
(2.7+1.2) atm 1.1 atm
At second equilibrium
(2.7+1.2-2x) atm (1.1+x) atm
The expression of :
Solving for x:
x = 0.3827 atm
The pressure of dinitrogen tetroxide after equilibrium is reached the second time:
(1.1+x) atm = (1.1+0.3827) atm =1.4827 atm ≈ 1.5 atm
1.5 atm is the pressure of dinitrogen tetroxide after equilibrium is reached the second time.
Answer: number of electron in respective sub shell or orbital
Explanation:
Answer:
The molarity of this KOH solutions 3.21 mol / L (option C is correct)
Explanation:
Step 1: Data given
Mass of KOH = 45.0 grams
Molar mass of KOH = 56.1 g/mol
Volume = 250.0 mL = 0.250 L
Step 2: Calculate moles KOH
Moles KOH = mass KOH / molar mass KOH
Moles KOH = 45.0 grams / 56.1 g/mol
Moles KOH = 0.802 moles
Step 3: Calculate molarity
Molarity KOH solution = moles KOH / volume water
Molarity KOH solution = 0.802 moles / 0.250 L
Molarity KOH solution = 3.21 mol / L
The molarity of this KOH solutions 3.21 mol / L (option C is correct)
Answer: it think it would be last one. the mouth to the stomach is the answer.
Explanation:
Prevent the release of toxic vapored, dusts, mists, or gases into the workplace air