Answer:
0.265
Explanation:
Draw a free body diagram. There are four forces:
Normal force Fn pushing up.
Weight force mg pulling down.
Tension force T at an angle θ.
Friction force Fn μ pushing left.
Sum the forces in the y direction:
∑F = ma
Fn + T sin θ − mg = 0
Fn = mg − T sin θ
Sum the forces in the x direction:
∑F = ma
T cos θ − Fn μ = 0
Fn μ = T cos θ
μ = T cos θ / Fn
μ = T cos θ / (mg − T sin θ)
Given T = 164 N, θ = 10.0°, m = 65.0 kg, and g = 9.8 m/s²:
μ = (164 N cos 10.0°) / (65.0 kg × 9.8 m/s² − 164 N sin 10.0°)
μ = 0.265
<span>This is best understood with Newtons Third Law of Motion: for every action there is an equal and opposite reaction. That should allow you to see the answer.</span>
Answer:
A because it is the most affective way to do it
Explanation:
Answer:
Q = 50.25 [J]
Explanation:
To solve this problem we must use the following equation that relates the temperature change with the mass and with the specific heat.
Q = m*Cp*(DT)
where:
Q = energy in form of heat [J]
m = mass = 5 [g] = 0.005 [kg]
Cp = specific heat = 1005 [J/kg*°C]
DT = temperature change = 10 [°C]
Now replacing:
Q = 0.005*1005*10
Q = 50.25 [J]
Answer:
The answer is C
Explanation:
Force is a vector quantity so it has both magnitude and direction. The question shows 20N act as magnitude and Southeast act as direction.
