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motikmotik
3 years ago
10

The electron structures of atoms are not involved in the emission of:

Physics
1 answer:
nekit [7.7K]3 years ago
7 0
The correct one is gamma rays. Lets go over them one by one.

Gamma rays are rays that arise from gamma decay, a type of radioactive decay. Often, after another decay, the nucleus is still unstable and it gives off energy in the form of gamma rays to stabilize itself. Hence, gamma rays have nothing to do with the electron structure, only with the nucleus of the atom.

X-rays are the product of accelerating electrons, hence only specific atoms can emit a specific energy of X-rays; similarly for the photoelectric phenomenon, the energy which is needed for photoelectrons to be created depends on the electron structure of the atom (in both cases, it is important to see how strong the bond between electron and atom is).
Finally, spectral lines differ depending on the electron structure of the atoms since electrons with different energies absorb different frequencies of light.
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What is electrical energy​
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Two closed organ pipe gives 4 beats when sounded together at 5°C. Calculate the number of beats in 35°C​
Gre4nikov [31]

Answer:

The number of beats is 10.58 in 35°C.

Explanation:

The beat frequency is given by : f₁-f₂

At 5°C, f₁-f₂ = 4

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The frequency in a standing wave is proportional to \sqrt T.

So,

\dfrac{f_1-f_2}{f_1'-f_2'}=\dfrac{\sqrt {T}}{\sqrt{T'}}\\\\f_1'-f_2'=(f_1-f_2)\times \dfrac{\sqrt{T'}}{\sqrt{T}}\\\\f_1'-f_2'=4\times \dfrac{\sqrt{35}}{\sqrt{5}}\\\\f_1'-f_2'=10.58

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7 0
3 years ago
What is the irradiance measured at a distance of 1 m and 2 m from a 1 W light point source
Paul [167]

Using the concepto of Irradiance which is the radiant flux (power) received by a surface per unit area we have that,

I = \frac{P}{A}

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P = Power

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The propagation of the irradiance is carried out in an area proportional to that of a sphere we will then have,

I = \frac{P}{4\pi r^2}

Irradiance at a distance of 1m from the source of light is

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Irradiance at a distance of 2m from the source of light is

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5 0
4 years ago
A net force of 24 N is acting on a 4.0-kg object. Find the acceleration in m/s2.
Inessa [10]

Hi there!

We can use Newton's Second Law:
\Sigma F = ma

ΣF = Net force (N)
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We can rearrange the equation to solve for the acceleration.

a = \frac{\Sigma F}{m}\\\\a = \frac{24}{4} = \boxed{6 \frac{m}{s^2}}

6 0
2 years ago
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