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4 years ago

How do you calculate acceleration

Physics

2 answers:

never [62]4 years ago

8 0

Answer:

As we know that acceleration is defined as the rate of change in velocity

So in order to find the acceleration of a given system we need to find the change in velocity of the given system with respect to time.

So here the formula is given as

$a = \frac{v_2 - v_1}{\Delta t}$

so in order to find the acceleration we need

$v_2$ = final velocity

$v_1$ = initial velocity

$\Delta t$ = time interval

so here we can say that acceleration calculation must need the change in velocity and the time taken to change the velocity both and the ration of this will give us the value of the acceleration

AfilCa [17]4 years ago

7 0

A=f/m
Example a=10/2
A=5

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Which type of stress causes deformation that leads to earthquakes at converging plate boundaries?

ki77a [65]

The answer is Compressional Stress

In geology, stress is the force per unit area that is placed on a rock. ... This is called confining stress. Compression squeezes rocks together, causing rocks to fold or fracture (break). Compression is the most common stress at convergent plate boundaries.

I hope this helped!! Have a great day :D

4 0

4 years ago

Of the following approximate conversions of celsius into fahrenheit, which is most accurate? a. 24°c almost-equals 75.9°f b. 2°c

Softa [21]

The most accurate among the options is 13°c almost-equals 55.0°f, when you round down 55.4, you get 55.0

Hence, option D) is the most accurate.

<h3>What is Scale of Temperature?</h3>

Scale of temperature is simply a method used in calibrating the physical quantity of temperature in metrology.

Conversion of Celsius into Fahrenheit, Formula is expressed as;

Degree = (0 × 9/5) + 32 = Fahrenheit

First we check each option;

A) 24°c almost-equals 75.9°f

24°C = (24 × 9/5) + 32 = 75.2°F

B) 2°C almost-equals 35.8°f

2°C = (2 × 9/5) + 32 = 35.6°F

C) 34°C almost-equals 92.7°f

34°C = (34 × 9/5) + 32 = 93.2°F

D) 13°c almost-equals 55.0°f

13°C = (13 × 9/5) + 32 = 55.4°F

The most accurate among the options is 13°c almost-equals 55.0°f, when you round down 55.4, you get 55.0

Hence, option D) is the most accurate.

Learn more about temperature scales here: brainly.com/question/88395

#SPJ4

4 0

2 years ago

The rms (root-mean-square) speed of a diatomic hydrogen molecule at 50∘C is 2000 m/s. Note that 1.0 mol of diatomic hydrogen at

denis-greek [22]

Answer:

A) d. (1/4)(2000m/s) = 500 m/s

B) c. 4000 J

C) f. None of the above (2149.24 m/s)

Explanation:

The translational kinetic energy of a gas molecule is given as:

K.E = (3/2)KT

where,

K = Boltzman's Constant = 1.38 x 1^-23 J/K

T = Absolute Temperature

but,

K.E = (1/2) mv²

where,

v = root mean square velocity

m = mass of one mole of a gas

Comparing both equations:

(3/2)KT = (1/2) mv²

v = √(3KT)/m _____ eqn (1)

FOR HYDROGEN:

v = √(3KT)/m = 2000 m/s _____ eqn (2)

FOR OXYGEN:

velocity of oxygen = √(3KT)/(mass of oxygen)

Here,

mass of 1 mole of oxygen = 16 m

velocity of oxygen = √(3KT)/(16 m)

velocity of oxygen = (1/4) √(3KT)/m

using eqn (2)

velocity of oxygen = (1/4)(2000 m/s) = 500 m/s

K.E = (3/2)KT

Since, the temperature is constant for both gases and K is also a constant. Therefore, the K.E of both the gases will remain same.

K.E of Oxygen = K.E of Hydrogen

K.E of Oxygen = 4000 J

using eqn (2)

At, T = 50°C = 323 k

v = √(3KT)/m = 2000 m/s

m = 3(1.38^-23 J/k)(323 k)/(2000 m/s)²

m = 3.343 x 10^-27 kg

So, now for this value of m and T = 100°C = 373 k

v = √(3)(1.38^-23 J/k)(373 k)/(3.343 x 10^-27 kg)

v = 2149.24 m/s

8 0

4 years ago

How do you calculate the braking distance

Anettt [7]

The braking distance is given by $s=\frac{-u^2}{2a}$

Explanation:

When the driver of a car hits the pedal of the brakes, the car starts decelerating until it stops. Assuming the deceleration is constant, then the motion is a uniformly accelerated motion, so we can use the following suvat equation:

$v^2-u^2=2as$