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Vinvika [58]
3 years ago
5

How do you calculate acceleration

Physics
2 answers:
never [62]3 years ago
8 0

Answer:

As we know that acceleration is defined as the rate of change in velocity

So in order to find the acceleration of a given system we need to find the change in velocity of the given system with respect to time.

So here the formula is given as

a = \frac{v_2 - v_1}{\Delta t}

so in order to find the acceleration we need

v_2 = final velocity

v_1 = initial velocity

\Delta t = time interval

so here we can say that acceleration calculation must need the change in velocity and the time taken to change the velocity both and the ration of this will give us the value of the acceleration

AfilCa [17]3 years ago
7 0
A=f/m
Example a=10/2
A=5
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What are the layers of the earth
AleksAgata [21]

Answer:

CRUST, UPPER MANTLE, LOWER MANTLE, INNER CORE, OUTER CORE,

Explanation:

how do u not know this

8 0
3 years ago
Calculate the period of a satellite orbiting the Moon, 98 kmkm above the Moon's surface. Ignore effects of the Earth. The radius
beks73 [17]

Answer:

3.6*10^18s

Explanation:

To find the period of the satellite

We need to apply kephler's third law

Which is

MP² = (4π²/G) d³

d=semi-major axis which is the distance from center of moon = 98km+1740km = 1838km

where M= mass of the moon = 7.3x10^22kg

P=period

G=newtonian gravatational constant= 6.67x10^-11

To find the Period solve for P

P = √[(4π²/G M)xd³]

P=√(4 π²/6.67x10^-22*7.3x10^22kg) x (1.838x10^6m)³]

= 3.6*10^18s

6 0
3 years ago
A 60.0 kg soccer player kicks a 0.4000 kg stationary soccer ball with 6.25 N of force. How fast does the soccer ball accelerate,
frozen [14]
F = ma
6.25 N = 0.4 kg · a
a = (6.25/0.4) m/s²      since N=kg·m/s²
a = 15.625 m/s² 

The answer is c) 15.6 m/s²
(Note that the mass of the soccer player is irrelevant.)
8 0
3 years ago
A person pushes on a box with a force of 500N. If the box does not move, what is the force of static friction on the box?
Alexxx [7]

Answer:

c

Explanation:

4 0
3 years ago
What could be the possible answer to the question ?<br><br>thankyou ~​
Ganezh [65]

The value of the force, F₀, at equilibrium is equal to the horizontal

component of the tension in string 2.

Response:

  • The value of F₀ so that string 1 remains vertical is approximately <u>0.377·M·g</u>

<h3>How can the equilibrium of forces be used to find the value of F₀?</h3>

Given:

The weight of the rod = The sum of the vertical forces in the strings

Therefore;

M·g = T₂·cos(37°) + T₁

The weight of the rod is at the middle.

Taking moment about point (2) gives;

M·g × L = T₁ × 2·L

Therefore;

T_1 = \mathbf{\dfrac{M \cdot g}{2}}

Which gives;

M \cdot g = \mathbf{T_2 \cdot cos(37 ^{\circ})+ \dfrac{M \cdot g}{2}}

T_2 = \dfrac{M \cdot g - \dfrac{M \cdot g}{2}}{cos(37 ^{\circ})}  = \mathbf{\dfrac{M \cdot g}{2 \cdot cos(37 ^{\circ})}}}

F₀ = T₂·sin(37°)

Which gives;

F_0 = \dfrac{M \cdot g \cdot sin(37 ^{\circ})}{2 \cdot cos(37 ^{\circ})}} = \dfrac{M \cdot g \cdot tan(37 ^{\circ})}{2}  \approx  \mathbf{0.377  \cdot M \cdot g}

  • F₀ ≈ <u>0.377·M·g</u>

<u />

Learn more about equilibrium of forces here:

brainly.com/question/6995192

3 0
2 years ago
Read 2 more answers
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