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3 years ago

How do you calculate acceleration

Physics

2 answers:

never [62]3 years ago

8 0

Answer:

As we know that acceleration is defined as the rate of change in velocity

So in order to find the acceleration of a given system we need to find the change in velocity of the given system with respect to time.

So here the formula is given as

$a = \frac{v_2 - v_1}{\Delta t}$

so in order to find the acceleration we need

$v_2$ = final velocity

$v_1$ = initial velocity

$\Delta t$ = time interval

so here we can say that acceleration calculation must need the change in velocity and the time taken to change the velocity both and the ration of this will give us the value of the acceleration

AfilCa [17]3 years ago

7 0

A=f/m
Example a=10/2
A=5

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2 years ago

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spayn [35]

Answer:

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Explanation:

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On the other hand, there no initial velocity in the y-component, so the arrow is basically in free-fall.

Applying the equations of kinematics in the x-direction gives

$x - x_0 = v_{x_0} t + \frac{1}{2}a_x t^2\\63 \times 10^{-3} = v_0t + 0\\t = \frac{63\times 10^{-3}}{v_0}$

For the y-direction gives

$v_y = v_{y_0} + a_y t\\v_y = 0 -9.8t\\v_y = -9.8t$

Combining both equation yields the y_component of the final velocity

$v_y = -9.8(\frac{63\times 10^{-3}}{v_0}) = -\frac{0.61}{v_0}$

Since we know the angle between the x- and y-components of the final velocity, which is 180° - 2.8° = 177.2°, we can calculate the initial velocity.

$\tan(\theta) = \frac{v_y}{v_x}\\\tan(177.2^\circ) = -0.0489 = \frac{v_y}{v_0} = \frac{-0.61/v_0}{v_0} = -\frac{0.61}{v_0^2}\\v_0 = 3.53~{\rm m/s}$

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