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Artist 52 [7]
3 years ago
12

Two sinusoidal waves are identical except for their phase. When these two waves travel along the same string, for which phase di

fference will the amplitude of the resultant wave be a maximum?
Physics
1 answer:
Kamila [148]3 years ago
6 0

Answer:

zero or 2π is maximum

Explanation:

Sine waves can be written

      x₁ = A sin (kx -wt + φ₁)

     x₂ = A sin (kx- wt + φ₂)

When the wave travels in the same direction

      Xt = x₁ + x₂

      Xt = A [sin (kx-wt + φ₁) + sin (kx-wt + φ₂)]

We are going to develop trigonometric functions, let's call

     a = kx + wt

     Xt = A [sin (a + φ₁) + sin (a + φ₂)

We develop breasts of double angles

     sin (a + φ₁) = sin a cos φ₁ + sin φ₁ cos a

    sin (a + φ₂) = sin a cos φ₂ + sin φ₂ cos a

Let's make the sum

     sin (a + φ₁) + sin (a + φ₂) = sin a (cos φ₁ + cos φ₂) + cos a (sin φ₁ + sinφ₂)

to have a maximum of the sine function, the cosine of fi must be maximum

     cos φ₁ + cos φ₂ = 1 +1 = 2

the possible values ​​of each phase are

     φ1 = 0, π, 2π  

     φ2 = 0, π, 2π,  

so that the phase difference of being zero or 2π is maximum

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What is the kinetic energy of a toy truck with a mass of 0.75 kg and a velocity of 4 m/s? (Formula: )
Dvinal [7]

Answer: Option (b) is the correct answer.

Explanation:

Kinetic energy is the energy of an object or particle when it is in motion.

Mathematically,   Kinetic energy = \frac{1}{2}mass \times (velocity)^{2}

It is given that toy truck has mass = 0.75 kg, and velocity = 4 m/s.

Calculate the kinetic energy as follows.

           Kinetic energy = \frac{1}{2}mass \times (velocity)^{2}

                                    = \frac{1}{2}0.75 kg \times (4 m/s)^{2}

                                     = \frac{1}{2}0.75 kg \times 16 m^{2}/s^{2}

                                     = 0.75 kg \times 8 m^{2}/s^{2}

                                     =  6 kg m^{2}/s^{2}

or,       Kinetic energy = 6 joules

Thus, we can conclude that kinetic energy of toy truck is 6 J.


6 0
4 years ago
Read 2 more answers
A uniform meter stick is pivoted at the 50.00 cm mark on the meter stick. A 400.0 gram object is hung at the 20.0 cm mark on the
babunello [35]

Answer:C

Explanation:

Given

mass m_1=400\ gm is at x=20\ cm mark

mass m_2=320\ gm is at x=75\ cm mark

Scale is Pivoted at x=50\ cm mark

For scale to be in equilibrium net torque must be equal to zero

Taking ACW as positive thus

T_{net}=0.4\times g\times (0.5-0.2)-0.32\times g\times(0.75-0.50)

T_{net}=0.12g-0.08g=0.04g

Therefore a net torque of 0.04 g is required in CW sense which a mass 400\ gm can provide at a distance of x_o from pivot

0.04g=0.4\times g\times x_o

x_o=0.1\ m

therefore in meter stick it is at a distance of x=60\ cm

6 0
3 years ago
What is the internal energy of 3.00 mol of N2 gas at 25 degrees C? To solve this problem, use the equation: U electronic gas = 5
allochka39001 [22]

<u>Given data</u>

Determine Internal energy of gas N₂,  (U) = ?

Temperature (T) = 25° C

                          = 25+273 = 298 K,

Gas constant (R) = 8.31 J/ mol-K ,

Number of moles (n) = 3 moles,

<u>Internal energy of N₂ </u>

Internal energy is a property of thermodynamics, the concept of internal energy can be understand by ideal gas. For example N₂, the observations for oxygen and nitrogen at atmospheric temperatures,  f=5,  (where f is translational  degrees of freedom).

       So per kilogram of gas,

          The internal energy (U) = 5/2 .n.R.T

                                                  = (5/2) × 3 × 8.31 ×298

                                                  = 18572.85 J

<em>The internal energy of the N₂ is 18,572.85 J and it is approximately equal to 18,600 J given in the option B.</em>

 



8 0
3 years ago
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mixas84 [53]

Answer:

-3.1512

Explanation:

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4 0
3 years ago
Two planets have the same surface gravity, but planet b has twice the radius of planet
nevsk [136]
The formula for the acceleration due to gravity is:

a = Gm/r²
where
G is the universal gravitational constant = 6.6726 x 10⁻¹¹ N-m²/kg²
m is the mass of planet
r is the radius of planet

So, if they have the same a:

m₁/r₁² = m₂/r₂²
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m/r₁² = m₂/(2r₁)²
m₂ = 4m

<em>Thus, the answer is D.</em>
8 0
4 years ago
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