Answer:
106 single crossover events
Explanation:
Total number of offspring = 1250
<u>Determine the number of offspring that would be expected </u>
( Rf between the genes vg and Pr ) * ( Total number of progeny )
= 0.125 * 1250 ≈ 156 ( value for single and double crossovers )
next :
( value of the Rf of double crossovers ) * ( Total number of progeny )
= (0.322 * 0.125) = 0.04025 * 1250 = 50
Hence the number of offspring expected to obtain/represent a single crossover event between pr and vg
= 156 - 50 = 106
I’m not sure if this will help but I found: https://prezi.com/l0fa6du3b9kp/going-off-the-grid-assignment/?fallback=1 and
Answer:
Δ KE = -495 J
Explanation:
given,
mass of the ice hockey player = 110 Kg
initial speed = 3 m/s
final speed = 0 m/s
distance, d = 0.3 m
change in kinetic energy


Δ KE = -495 J
Hence, the change in kinetic energy is equal to Δ KE = -495 J
Answer:
Option B. 6.25 J/S
Explanation:
Data obtained from the question include:
t (time) = 2secs
F (force) = 50N
d (distance) = 0.25m
P (power) =?
The power can be obtained by using the formula P = workdone/time.
P = workdone / time
P = (50 x 0.25)/ 2
P = 6.25J/s