For part a)
Since the conical surface is not exposed to the radiation coming from the walls only from the circular plate and assuming steady state, the temperature of the conical surface is also equal to the temperature of the circular plate. T2 = 600 K
For part b)
To maintain the temperature of the circular plate, the power required would be calculated using:
Q = Aσ(T₁⁴ - Tw⁴)
Q = π(500x10^-3)²/4 (5.67x10^-8)(600⁴ - 300⁴)
Q = 5410.65 W
The blue star is the hottest star.
Fun Fact: The coldest stars are red
The answer is A because it gives you a straight line which would make it easy for you go just go to end fast as a car .
okay , but what is this i dont understand .
Answer:
The current at time t = 4.00 s is 0.766 A.
Explanation:
Given that,
The quantity of charge through a conductor is modeled as :
We need to find the current (in A) at time t = 4.00 s. We know that the rate of change of electric charge is called electric current. It is given by :
At t = 4 s
So, the current at time t = 4.00 s is 0.766 A. Hence, this is the required solution.
