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Alik [6]
4 years ago
12

The color red that we see depends upon the :

Physics
2 answers:
andrew-mc [135]4 years ago
8 0
<h3>✽ - - - - - - - - - - - - - - - ~<u>Hello There</u>!~ - - - - - - - - - - - - - - - ✽</h3>

➷ The correct answer should be D. wavelength of the red light wave

<h3><u>✽</u></h3>

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

Anastaziya [24]4 years ago
7 0

if i am correct the answer is d. because depending on how far a wavelength goes we see different colors.

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Idk maybe excersice everyday
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a motorcycle at a stoplight takes 4.22 seconds to accelerate to 28.0 m/s after thew light turns green. what is its average accel
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4 years ago
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A 0.280-kg croquet ball makes an elastic head-on collision with a second ball initially at rest. The second ball moves off with
Jet001 [13]

Answer:

mass of second ball is 0.84 kg

Explanation:

mass of ball = 0.280 kg

to find out

mass of the second ball

solution

we know here elastic head on collision and

second ball moves =  half the original speed

we consider here m1 mass of 1st ball and m2 mass of second ball

v1 = velocity of first ball before collision

v2 = velocity of second ball before collision

v3 = velocity of first ball after collision

v4 = velocity of second ball after collision

so here

we know 2nd ball was on rest so v2 = 0

after collision v4 = 1/2 ( v1)

and we know head on collision so

v3 = - v1/2

so from law of conservation of mass

m1v1 + m2v2 = m1v3 + m2v4

put here value

m1v1 + m2(0) = m1(-v1/2) + m2(v1/2)

solve and we get

m2 = 3m1

m2 = 3( 0.280) = 0.84

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7 0
4 years ago
If the plates are pulled twice as far apart, but are kept connected to the battery, the electric field between the plates will b
never [62]

Electric field between two parallel plates will be halved as it was before.

What is the electric field between two plates:

The electric field lines of two parallel plates can be represented by straight lines perpendicular to both plates surfaces while carrying arrows that point from +Q plate A toward -Q plate B.

we know that,

The electric field between plates:

E=V / d

where,

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d is separation distance between plates.

now If the plates are pulled twice as far apart, but are kept connected to the battery,

the separation distance becomes,

d' = 2d

so the new electric field will be:

E' = V / d'

substituting the values,

E' = V / ( 2d )

E' = 1/2 ( V /d )

E' = 1/2 E

hence we can conclude that

Electric field between plates will be halved as it was before.

Learn more about Electric field between plates here:

<u>brainly.com/question/14788793</u>

#SPJ4

7 0
2 years ago
ou slide a slab of dielectric between the plates of a parallel-plate capacitor. As you do this, the charges on the plates remain
Sav [38]

Answer:

Explanation:

Energy stored in a capacitor is given by the expression

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Hence energy decreases.

8 0
4 years ago
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