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4 years ago

Igneous rocks formed below earths surface

Chemistry

2 answers:

marin [14]4 years ago

7 0

Answer:

The answer is C. Instrusive

Explanation:

The ingneas rocks are those that form when the magma cools and reaches a solid state. When this type of volcanic rock cooling occurs below the surface of the earth's crust, it is known as intrusive rocks. This type of igneous rock is formed from the magma that has solidified, creating crystals.

slava [35]4 years ago

3 0

Answer:

A) igneous rocks

Explanation:

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The sum of the first 10 terms of an arithmetic progression is 120 and the sum of first twenty is 840. find sum of first 30 terms

STatiana [176]

Answer:

The sum of first 30 terms of the arithmetic progression is <u>2160.</u>

Explanation:

For an arithmetic progression, the sum of first $n$ terms with first term as $a$ and common difference $d$ is given as:

$S_n=\frac{n}{2}(2a+(n-1)d)$

Now, it is given that:

$For\ n=10,S_n=120\\For\ n=20,S_n=840$

Now, plug in these values and frame two equations in $a\ and\ d$

$S_{10}=\frac{10}{2}(2a+(10-1)d)\\120=5(2a+9d)\\2a+9d=\frac{120}{5}\\2a+9d=24------------1$

$S_{20}=\frac{20}{2}(2a+(20-1)d)\\840=10(2a+19d)\\2a+19d=\frac{840}{10}\\2a+19d=84-----------2$

Now, we solve equations (1) and (2) for $a\ and\ d$ . Subtract equation (1) from equation (2). This gives,

$2a+19d-2a-9d=84-24\\19d-9d=60\\10d=60\\d=\frac{60}{10}=6$

Now, plug in the value of $d=6$ in equation (1) and solve for $a$ .

$2a+9(6)=24\\2a+54=24\\2a=24-54\\2a=-30\\a=\frac{-30}{2}=-15$

Plug in the values of $a=-15,\ n=30\ and\ d=6$ in the sum formula to find the sum of first 30 terms.

Now, the sum of first 30 terms is given as:

$S_{30}=\frac{30}{2}(2(-15)+(30-1)(6))\\S_{30}=15(-30+29(6))\\S_{30}=15(-30+174)\\S_{30}=15(144)=2160$

Therefore, the sum of first 30 terms of the arithmetic progression is 2160.

4 0

3 years ago

If you have 4.01 g of H2, how many grams of NH3 can be produced?

stellarik [79]

Answer:

136.5886g of NH3

Explanation:

N2 + 3H2 = 2NH3

The mass of the N2 = 4.01

3H2 has a 2/1 ratio

This means the mass of 3H2 is twice as much as N2.

NH3= 2*N2 = 2*4.01 = 8.02 of NH3

Then, by multiplying the mass by MX (17.031)

8.02*17.031=136.5886g can be produced. Round it if needed.

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ololo11 [35]

Answer:

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