<u>Answer:</u>
<u>For a:</u> The theoretical yield of carbon dioxide is 9.28 grams.
<u>For b:</u> The percent yield of the reaction is 72.2 %.
<u>Explanation:</u>
To calculate the number of moles, we use the equation:
.....(1)
Given mass of carbon monoxide = 5.91 g
Molar mass of carbon monoxide = 28 g/mol
Putting values in equation 1, we get:
![\text{Moles of carbon monoxide}=\frac{5.91g}{28g/mol}=0.211mol](https://tex.z-dn.net/?f=%5Ctext%7BMoles%20of%20carbon%20monoxide%7D%3D%5Cfrac%7B5.91g%7D%7B28g%2Fmol%7D%3D0.211mol)
The chemical equation for the reaction of carbon monoxide and oxygen gas follows:
![2CO(g)+O_2(g)\rightarrow 2CO_2(g)](https://tex.z-dn.net/?f=2CO%28g%29%2BO_2%28g%29%5Crightarrow%202CO_2%28g%29)
By Stoichiometry of the reaction:
2 moles of carbon monoxide produces 2 moles of carbon dioxide
So, 0.211 moles of carbon monoxide will produce =
of carbon dioxide
Now, calculating the mass of carbon dioxide by using equation 1, we get:
Molar mass of carbon dioxide = 44 g/mol
Moles of carbon dioxide = 0.211 mol
Putting values in equation 1, we get:
![0.211mol=\frac{\text{Mass of carbon dioxide}}{44g/mol}\\\\\text{Mass of carbon dioxide}=(0.211mol\times 44g/mol)=9.28g](https://tex.z-dn.net/?f=0.211mol%3D%5Cfrac%7B%5Ctext%7BMass%20of%20carbon%20dioxide%7D%7D%7B44g%2Fmol%7D%5C%5C%5C%5C%5Ctext%7BMass%20of%20carbon%20dioxide%7D%3D%280.211mol%5Ctimes%2044g%2Fmol%29%3D9.28g)
Hence, the theoretical yield of carbon dioxide is 9.28 grams.
To calculate the percentage yield of carbon dioxide, we use the equation:
![\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100](https://tex.z-dn.net/?f=%5C%25%5Ctext%7B%20yield%7D%3D%5Cfrac%7B%5Ctext%7BExperimental%20yield%7D%7D%7B%5Ctext%7BTheoretical%20yield%7D%7D%5Ctimes%20100)
Experimental yield of carbon dioxide = 6.70 g
Theoretical yield of carbon dioxide = 9.28 g
Putting values in above equation, we get:
![\%\text{ yield of carbon dioxide}=\frac{6.70g}{9.28g}\times 100\\\\\% \text{yield of carbon dioxide}=72.2\%](https://tex.z-dn.net/?f=%5C%25%5Ctext%7B%20yield%20of%20carbon%20dioxide%7D%3D%5Cfrac%7B6.70g%7D%7B9.28g%7D%5Ctimes%20100%5C%5C%5C%5C%5C%25%20%5Ctext%7Byield%20of%20carbon%20dioxide%7D%3D72.2%5C%25)
Hence, the percent yield of the reaction is 72.2 %.