All categories

3 years ago

What is the net ionic equation for the reaction shown below?

Chemistry

1 answer:

arsen [322]3 years ago

4 0

Answer:

Ag⁺(aq) + Cl⁻(aq) → AgCl(s)

Explanation:

Chemical equation:

AgNO₃(aq) + NaCl(aq) → AgCl(s) + NaNO₃(aq)

Balance chemical equation:

AgNO₃(aq) + NaCl(aq) → AgCl(s) + NaNO₃(aq)

Ionic equation

Ag⁺(aq)+ NO₃⁻(aq) + Na⁺(aq)+ Cl⁻(aq) → AgCl(s) + Na⁺(aq)+ NO₃⁻(aq)

Net ionic equation:

Ag⁺(aq) + Cl⁻(aq) → AgCl(s)

The NO₃⁻((aq) and Na⁺ (aq) are spectator ions that's why these are not written in net ionic equation. The AgCl can not be splitted into ions because it is present in solid form.

Spectator ions:

These ions are same in both side of chemical reaction. These ions are cancel out. Their presence can not effect the equilibrium of reaction that's why these ions are omitted in net ionic equation.

You might be interested in

Why are Sodium (Na) and Chlorine (CI) considered ions when reacting with<br> each other?

vlada-n [284]

The bonds in salt compounds are called ionic because they both have an electrical charge—the chloride ion is negatively charged and the sodium ion is positively charged.

7 0

3 years ago

Liquid sodium is being considered as an engine coolant. How many grams of liquid sodium (minimum) are needed to absorb 1.20 MJ 1

mars1129 [50]

Answer : The mass of liquid sodium needed are, $3.17\times 10^3g$

Explanation :

First we have to calculate the number of moles of liquid sodium.

$q=n\times c\times (\Delta T)$

where,

q = heat absorb = 1.20 MJ = 1.20 × 10⁶ J

n = number of moles of liquid sodium = ?

c = specific heat capacity = $30.8J/mol.K$

$\Delta T$ = change in temperature = $10.0^oC=273+10.0=283K$

Now put all the given values in the above formula, we get:

$1.20\times 10^6J=n\times 30.8J/mol.K\times 283K$

$n=137.7mol$

Now we have to calculate the mass of liquid sodium.

Molar mass of Na = 23 g/mol

$\text{Mass of Na}=\text{Moles of Na}\times \text{Molar mass of Na}$

$\text{Mass of Na}=137.7mol\times 23g/mol=3167.1g=3.17\times 10^3g$

Therefore, the mass of liquid sodium needed are, $3.17\times 10^3g$

3 0

4 years ago

Given the propane molecule C3H8(g)! a) What is the balanced equation for the combustion of propane in O2?(20 pts.) b) What is th

lubasha [3.4K]

Answer:

The answer to your question is below

Explanation:

Propane = C₃H₈

Process

1.- Write the chemical reaction

C₃H₈ + O₂ ⇒ CO₂ + H₂O

balanced chemical reaction

C₃H₈ + 5O₂ ⇒ 3CO₂ + 4H₂O

Reactants Elements Products

3 C 3

8 H 8

10 O 10

b) Standard enthalpy

Propane -104.7 kJ/mol

Oxygen 0 kJ/mol

Carbon dioxide -393.5 kJ/mol

Water -241.8 kJ/mol

ΔH° = ∑ΔH° products - ∑H° reactants

ΔH° = 3(-393.5) + 4(-241.8) - [(-104.7) + 0]

-Simplification

ΔH° = -1180.5 kJ/mol - 967.2 kJ/mol + 104.7 kJ/mol

ΔH° = - 2042.5 kJ/mol

This reaction is exothermic because ΔH° is negative.

4 0

3 years ago

Is camphor heated a physical/chemical change

DedPeter [7]

Answer:

when it is heated it changes to vapor, which is a physical change

Explanation:

7 0

4 years ago

Menthol is a crystalline substance with a peppermint taste and odor. When 1.48 g of menthol is dissolved in 25.0 g of cyclohexan

pishuonlain [190]

Answer:

Molar mass of menthol is 155.86 g/mol

Explanation:

Let's apply the colligative property of freezing point depression:

ΔT = Kf . m . i

As menthol is an organic compound we assume the i (Van't Hoff factor as non electrolytic, so i = 1)

m = mol /kg (molality)

Kf = Cryoscopic constant, in this case, for cyclohexane

ΔT = T° freezing of pure solvent - T° freezing solution

7.90°C = 20.8°C / m . m . 1

7.90°C / 20.8 m/°C = m

0.380 m = molality

0.380 moles are the moles of solute (menthol) dissolved in 1kg of solvent, but our mass of solvent is 25 g.

Let's convert the g of solvent to kg to work with molality

25 g = 0.025 kg

molal . solvent mass = moles of solute

0.380 mol /kg . 0.025kg = 9.49×10⁻³ moles

Now, we have the moles and the mass of solute. Let's determine the molar mass of menthol (grams / moles)

1.48 g / 9.49×10⁻³ m = 155.86 g/m

4 0

4 years ago