All categories

3 years ago

56. 1-7x + 4) = 187. 5 p + 10 = 10

Mathematics

1 answer:

zubka84 [21]3 years ago

4 0

Answer:

$\large\boxed{6.\ x=-\dfrac{12}{7}}\\\boxed{7.\ p=0}$

Step-by-step explanation:

$6.\\\\1-7x+4=18\\(1+4)-7x=18\\5-7x=18\qquad\text{subtract 5 from both sides}\\-7x=12\qquad\text{divide both sides by (-7)}\\x=-\dfrac{12}{7}\\\\7.\\\\5p+10=10\qquad\text{subtract 10 from both sides}\\5p=0\qquad\text{divide both sides by 5}\\p=0$

You might be interested in

Find the midpoint of the segment with the following endpoints.<br> (4,2) and (7,6)

Tema [17]

Answer:

The answer is

Step-by-step explanation:

The midpoint M of two endpoints of a line segment can be found by using the formula

$M = ( \frac{x1 + x2}{2} , \: \frac{y1 + y2}{2} )$

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

(4,2) and (7,6)

The midpoint is

$M = ( \frac{4 + 7}{2} \: , \: \frac{2 + 6}{2} ) \\ = ( \frac{11}{2} \: , \: \frac{8}{2} )$

We have the final answer as

$( \frac{11}{2} \: , \: 4)$

Hope this helps you

4 0

3 years ago

What is the surface area ,in square meters of the toy box

salantis [7]

Answer:426m^2

Step-by-step explanation:

8 0

3 years ago

Solve (x + 4)2 – 3(x + 4) – 3 = 0 using substitution. u = Select the solution(s) of the original equation.

bezimeni [28]

Answer:

$\dfrac{-5-\sqrt{21}}{2},\ \dfrac{-5+\sqrt{21}}{2}$

Step-by-step explanation:

For the equation $(x+4)^2-3(x+4)-3=0$ use the substitution $u=x+4.$ Then the equation will take look

$u^2-3u-3=0.$

Solve this quadratic equation:

$D=(-3)^2-4\cdot 1\cdot (-3)=9+12=21,\\ \\u_{1,2}=\dfrac{-(-3)\pm \sqrt{21}}{2}=\dfrac{3\pm\sqrt{21}}{2}.$

Thus,

$x+4=\dfrac{3-\sqrt{21}}{2}\text{ or }x+4=\dfrac{3+\sqrt{21}}{2},\\ \\x_1=\dfrac{3-\sqrt{21}}{2}-4=\dfrac{-5-\sqrt{21}}{2}\text{ or }x_2=\dfrac{3+\sqrt{21}}{2}-4=\dfrac{-5+\sqrt{21}}{2}.$

8 0

4 years ago

Read 2 more answers

The lengths of the sides of a right triangle can be

Otrada [13]

The answer is A. 9, 12, 15,

8 0

3 years ago

Pablo and max's follows a flight pattern approximatley modled by the equation h(t)=-8t^2+16t+2 where h(t)is their rocket's heigh

kodGreya [7K]

Answer: 2.11 s

Step-by-step explanation:

Given

Equation of rockets height is given by

$\Rightarrow h(t)=-8t^2+16+2$

Height will be zero once the rocket lands on the ground

So, we can write

$\Rightarrow h(t)=0\ \text{or}\ -8t^2+16t+2=0\\\Rightarrow 8t^2-16t-2=0\\\\\Rightarrow t=\dfrac{16\pm \sqrt{(-16)^2-4(8)(-2)}}{2\times 8}\\\\\Rightarrow t=\dfrac{16\pm \sqrt{320}}{16}\\\\\text{Neglecting negative value of t}\\\\\Rightarrow t=\dfrac{16+17.888}{16}=2.11\ s$

7 0

3 years ago

56. 1-7x + 4) = 187. 5 p + 10 = 10​

56. 1-7x + 4) = 187. 5 p + 10 = 10