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dexar [7]
3 years ago
9

Find the mass in grams of 0.327 liters of AL

Chemistry
1 answer:
Assoli18 [71]3 years ago
6 0

Answer:

883g

Explanation:

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Based on location in the periodic table, which element has chemical properties that are most similar to iodine
Ymorist [56]

Based on location in the periodic table, fluorine (F) has chemical properties that are most similar to iodine.

In the periodic table, elements are classified in groups and periods. The elements in the same group are chemically similar and they have the same number of valence electrons. Elements in the same period have the same highest energy level.

Hence, when looking for an element that is most chemically similar to iodine, we have to consider the element that is in the same group with iodine.

Both fluorine are iodine are both in group 17 hence, fluorine is most chemically similar to iodine.

Learn more: brainly.com/question/11155928

3 0
3 years ago
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If the volume and Kelvin temperature are reduced by one-half what will happen to the pressure???
jolli1 [7]

Answer:

the pressure will decrease

Explanation:

6 0
3 years ago
Find the mass in 2.6 mole of lithium bromide
Tresset [83]

Answer:

2.6 mole of lithium bromide have 225.81 g.

Explanation:

Given data:

Number of moles of lithium bromide = 2.6 mol

Mass of lithium bromide = ?

Solution:

Formula:

<em>Number of moles = mass/ molar mass</em>

Molar mass of lithium bromide = 86.85 g/mol

Mass = number of moles × molar mass

Mass = 2.6 mol ×86.85 g/mol

Mass = 225.81 g

Thus 2.6 mole of lithium bromide have 225.81 g.

5 0
3 years ago
What factor is used to classify acids as strong or weak?
hoa [83]
The extent of dissociation into hydrogen ions in water. A strong acid dissociates completely into hydrogen ions in water whereas a weak acid only dissociates partially
3 0
3 years ago
A swimmer can inhale exactly 0.25 moles of air before diving underwater. What will be the total volume of the swimmer’s lungs at
Crank

Answer:

6.14 L

Explanation:

To answer this question we'll<u> use the PV=nRT formula</u>, where:

  • P = 0.97 atm
  • V = ?
  • n = 0.25 mol
  • R = 0.082 atm·L·mol⁻¹·K⁻¹
  • T = 17.6 °C ⇒ 17.6 + 273.16 = 209.76 K

We <u>input the data</u>:

  • 0.97 atm * V = 0.25 mol * 0.082 atm·L·mol⁻¹·K⁻¹ * 209.76 K

And <u>solve for V</u>:

  • V = 6.14 L
6 0
3 years ago
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