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Alina [70]
3 years ago
6

How many moles of cl- ions are needed to completely combine with 0.25 moles of mg+2 ions? 0.175 0.75 0.50 0.25 0.125?

Chemistry
1 answer:
Solnce55 [7]3 years ago
6 0
When magnesium ions and chloride ions form a compound the chemical formula would be MgCl2 which means that for every 1 atom of Mg+ there would be 2 atoms of Cl- bonded. This would be proportional to units of moles.

Moles Cl- = 0.25 mol Mg2+ ( 2 mol Cl - / 1 mol Mg2+) = 0.50 mol Cl- would be needed
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2 years ago
What is the vapor pressure of the solution if 35.0 g of water is dissolved in 100.0 g of ethyl alcohol at 25 ∘C? The vapor press
masya89 [10]

<u>Answer:</u> The vapor pressure of the solution is 43.55 mmHg

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}      .....(1)

  • <u>For water:</u>

Given mass of water = 35.0 g

Molar mass of water = 18 g/mol

Putting values in equation 1, we get:

\text{Moles of water}=\frac{35.0g}{18g/mol}=1.944mol

  • <u>For ethyl alcohol:</u>

Given mass of ethyl alcohol = 100.0 g

Molar mass of ethyl alcohol = 46 g/mol

Putting values in equation 1, we get:

\text{Moles of ethyl alcohol}=\frac{100.0g}{46g/mol}=2.174mol

Total moles of solution = [1.944 = 2.174] moles = 4.118 moles

  • Mole fraction of a substance is given by:

\chi_A=\frac{n_A}{n_A+n_B}

<u>For water:</u>

\chi_{\text{water}}=\frac{n_{\text{water}}}{n_{\text{water}}+n_{\text{ethyl alcohol}}}

\chi_{water}=\frac{1.944}{4.118}=0.472

<u>For ethyl alcohol:</u>

\chi_{\text{ethyl alcohol}}=\frac{n_{\text{ethyl alcohol}}}{n_{\text{water}}+n_{\text{ethyl alcohol}}}

\chi_{\text{ethyl alcohol}}=\frac{2.174}{4.118}=0.528

Dalton's law of partial pressure states that the total pressure of the system is equal to the sum of partial pressure of each component present in it.

To calculate the vapor pressure of the solution, we use the law given by Dalton, which is:

P_T=\sum_{i=1}^n (p_i\times \chi_i)

Or,

P_T=[(p_{\text{water}}\times \chi_{\text{water}})+(p_{\text{ethyl alcohol}}\times \chi_{\text{ethyl alcohol}}

We are given:

Vapor pressure of water = 23.8 mmHg

Vapor pressure of ethyl alcohol = 61.2 mmHg

Putting values in above equation, we get:

p_T=[(23.8\times 0.472)+(61.2\times 0.528)]\\\\p_T=43.55mmHg

Hence, the vapor pressure of the solution is 43.55 mmHg

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