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hodyreva [135]
3 years ago
11

A compass needle points north when let it move freely. why do scientist think this happened?​

Chemistry
1 answer:
bezimeni [28]3 years ago
4 0

Answer:

because of...

Explanation:

The earth's magnetic field.

(i dont know if that is what youre looking for, but that is what i know.... hope it helps!!!)

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Calculate the mass in grams of iodine (i 2 ) that will react completely with 20.4 g of aluminum (al) to form aluminum iodide (al
garik1379 [7]
3I₂ + 2Al → 2AlI₃

m(I₂)=3M(I₂)m(Al)/{2M(Al)}

m(I₂)=3*253.8*20.4/{2*27.0}=287.64 g
8 0
3 years ago
What is the energy released in this β − β − nuclear reaction 40 19 K → 40 20 C a + 0 − 1 e 19 40 K → 20 40 C a + − 1 0 e ? (The
Effectus [21]

<u>Answer:</u> The energy released in the given nuclear reaction is 1.3106 MeV.

<u>Explanation:</u>

For the given nuclear reaction:

_{19}^{40}\textrm{K}\rightarrow _{20}^{40}\textrm{Ca}+_{-1}^{0}\textrm{e}

We are given:

Mass of _{19}^{40}\textrm{K} = 39.963998 u

Mass of _{20}^{40}\textrm{Ca} = 39.962591 u

To calculate the mass defect, we use the equation:

\Delta m=\text{Mass of reactants}-\text{Mass of products}

Putting values in above equation, we get:

\Delta m=(39.963998-39.962591)=0.001407u

To calculate the energy released, we use the equation:

E=\Delta mc^2\\E=(0.001407u)\times c^2

E=(0.001407u)\times (931.5MeV)    (Conversion factor:  1u=931.5MeV/c^2  )

E=1.3106MeV

Hence, the energy released in the given nuclear reaction is 1.3106 MeV.

6 0
2 years ago
HELP!! BEST ANSWER GETS BRAINLIEST!!
vampirchik [111]
<span> The anwser is D. Radiation, because it can travel thru air.</span>
4 0
3 years ago
If a student puts 2.7 moles of gas in a container with a volume of 57.0 and at a temperature of 127°C what is the pressure insid
Delvig [45]
23 would be the answer actually idk I just need to answer some answers
7 0
3 years ago
What assumptions do we make in order to use the Henderson-Hasselbalch equation? a. Both the weak acid and its conjugate base are
zepelin [54]

Answer:

The final and initial concentration of the acid and it's conjugate base are approximately equal, that is we use the weak acid approximation.

Explanation:

The Henderson-Hasselbalch is used to calculate the pH of a buffer solution. It depends on the weak acid approximation.

Since the weak acid ionizes only to a small extent, then we can say that [HA] ≈ [HA]i

Where [HA] = final concentration of the acid and [HA]i = initial concentration of the acid.

It also follows that [A^-] ≈ [A^-]i where [A^-] and[A^-]i refer to final and initial concentrations of the conjugate base hence the answer above.

7 0
2 years ago
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