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SOVA2 [1]
3 years ago
8

To prepare 100.0 mL of a 0.0525 M solution of NaCl in water, what mass of sodium chloride is needed? The

Chemistry
1 answer:
tangare [24]3 years ago
6 0

Answer:

0.307 g

Explanation:

Step 1: Given data

Volume of solution: 100.0 mL

Molarity of the NaCl solution: 0.0525 M

Molar mass of NaCl: 58.44 g/mol

Step 2: Calculate the moles of NaCl required

The molarity is equal to the moles of solute (NaCl) divided by the liters of solution.

M = moles of NaCl / liters of solution

moles of NaCl = M × liters of solution

moles of NaCl = 0.0525 mol/L × 0.1000 L = 5.25 × 10⁻³ mol

Step 3: Calculate the mass corresponding to 5.25 × 10⁻³ moles of NaCl

5.25 × 10⁻³ mol × 58.44 g/mol = 0.307 g

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1) p⁺ = 9; number of protons.
Fluorine has a<span>tomic number Z = 9 (total number of protons).
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In element number of electrons and protons are the same, because element has neutral charge, but because in this example, fluorine is anion with negative charge, it has one electron more.
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3 years ago
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marishachu [46]
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3 years ago
Which of the following does not apply to water molecules?
serg [7]

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It is the last one.

Explanation:

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2 years ago
Why are ions charged particles?
Deffense [45]

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Explanation:

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8 0
3 years ago
A measured sample of argon gas has a volume of 20.0 L at a pressure of 660 mm Hg. What is the final volume
valkas [14]

Answer:

C . 24 L

Explanation:

Given data:

Initial volume of gas = 20.0 L

Initial pressure of gas = 660 mmHg

Final volume = ?

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Solution:

The given problem will be solved through the Boly's law,

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Mathematical expression:

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3 years ago
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